# [GAMBIT] What is the shape parameter in "Create Conic Arc" tool ?

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 November 21, 2012, 03:02 What is the shape parameter in "Create Conic Arc" tool ? #1 New Member   Join Date: Nov 2012 Posts: 3 Rep Power: 5 Hi everyone I was trying to create a conic arc which passes through 3 points using the tool in Gambit with an exact value of eccentricity ( 0 to infinity, 1 is a parabola, greater than 1 for hyperbolas), however, the tool in Gambit does not allow me to enter the eccentric value. Instead, it asks for a number called shape parameter (0.01 to 0.99, 0.5 is a parabola, hyperbola is between 0.5 and 0.99). Is there a way for me to convert between the two quantities ? Thanks

 November 21, 2012, 03:54 #2 Super Moderator     Maxime Perelli Join Date: Mar 2009 Location: Switzerland Posts: 3,145 Rep Power: 32 http://aerojet.engr.ucdavis.edu/gamb...e_create_conic Do you have a sketch of what you want to draw? __________________ In memory of my friend Hervé: CFD engineer & freerider

 November 21, 2012, 05:16 #3 New Member   Join Date: Nov 2012 Posts: 3 Rep Power: 5 Basically I have 2 points and their midpoint is the center of the ellipses. I need to plot ellipses which pass through those two points with the symetry axis make a 45 degrees angle with the line connecting the two points and I need to vary the eccentricity of these ellipses. So how should I put the shoulder point to make the symetry axis tiled 45 degrees ?

 November 21, 2012, 05:51 #4 Super Moderator     Maxime Perelli Join Date: Mar 2009 Location: Switzerland Posts: 3,145 Rep Power: 32 I would use ellipse surface tool http://aerojet.engr.ucdavis.edu/gamb...reate_prim_ell fix one radius, and le vary the other radius __________________ In memory of my friend Hervé: CFD engineer & freerider

 November 21, 2012, 08:00 #5 New Member   Join Date: Nov 2012 Posts: 3 Rep Power: 5 Because I am going to plot the hyperbola and parabola in later part of my project, thus, I need to use the conic section tool

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