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[ANSYS Meshing] Defining total thickness for inflation. What is growth rate?

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Old   August 13, 2013, 22:00
Default Defining total thickness for inflation. What is growth rate?
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Is there any way to define the total thickness for the amount of inflation layers you specify?

In local inflation, you have an option called "total thickness," but the name is very misleading since it only allows you to define the "maximum" thickness of the inflation layer rather than the "total" thickness of all inflation layers.


Also, what is growth rate for inflation?
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Old   August 14, 2013, 10:33
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there are 4 parameters; initial height, ratio, number of layers and total height.

You can 3 of them and the 4th will be calculated.

Total height is the total thickness when you specify the initial height, a growth ratio and a number of layers...

If you specify the total height, you need to leave one of the other parameters (usually height or ratio) blank so the equation isn't over constrained.

the growth ratio is the ratio of one layers thickness over the layer below it.
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Old   August 14, 2013, 12:31
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Quote:
Originally Posted by PSYMN View Post
there are 4 parameters; initial height, ratio, number of layers and total height.

You can 3 of them and the 4th will be calculated.

Total height is the total thickness when you specify the initial height, a growth ratio and a number of layers...

If you specify the total height, you need to leave one of the other parameters (usually height or ratio) blank so the equation isn't over constrained.

the growth ratio is the ratio of one layers thickness over the layer below it.
Under "Inflation Option," I can choose from one of the following:
1) total thickness (which actually defines the maximum thickness of one thickest layer)
2) first layer thickness
3) smooth transition
4) first aspect ratio
5) last aspect ratio
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Old   August 14, 2013, 12:36
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Oh, sorry, you are using ANSYS Meshing. I was talking about ICEM CFD. My bad...

Take a quick look at the help for the definitions and for how to setup prism differently.
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