|April 18, 2011, 22:59||
The reduction in computational effort-urgent
Join Date: Apr 2011
Posts: 1Rep Power: 0
Hello everybody, I do have an urgent question..
I modeled a beam , using symmetry I just modeled one-fourth of the beam. I constrained the beam in cutting planes.. anyways.
I just want to know by reducing the size of the model four time, ( the number of nodes , and number of elements) how much my matrix operation is reduced. how does it relate to the total computational effort ?
I know the stiffness matrix will be one-fourth and the number of the components will be one/16th , but does this mean that the front matrix will be one/16th in each side !?
noting that I just used normal solid elements with three DOFs at each node.
please help me , your help in any extent is very much appreciated !
|May 2, 2011, 04:39||
Join Date: May 2011
Location: London, UK
Posts: 45Rep Power: 5
consider u have 'n' nodes. The size of your stiffness matrix will be 3n x 3n. If you reduce the number of nodes by 1/4 th, the size of the new stiffness matrix will be 3(n/4)x3(n/4). So you reduce n/16 numbers in the stiffness matrix. This implies a reduction in computational cost by (n/16)^2.
|ansys, computational effort, matrix operations, symmetry|
|Thread||Thread Starter||Forum||Replies||Last Post|
|Urgent - Polyflow - particle tracking visualization -Urgent||shafaatht||ANSYS||0||October 13, 2010 04:56|
|very urgent||amar||FLUENT||2||May 2, 2009 19:48|
|free "Computational Mechanics"||noname||Main CFD Forum||0||March 2, 2007 07:03|
|Short Course: Computational Thermal Analysis||Dean S. Schrage||Main CFD Forum||11||September 27, 2000 17:46|
|Relation between CFD and computational chemistry||Marc Segovia||Main CFD Forum||3||May 26, 1999 05:13|