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Old   October 18, 2000, 16:49
Default Star-CD and BC.
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Since I am just starting to use Star-CD, I would very much like to know how the turbulent boundary condition are applied in Star.

Ex. simple case: I have a 2d channel with a square cylinder in the middle of the channel.



Inlet -> | | Outlet ->



Since the inlet and outlet are easy to specify and also the top and bottom walls of the channel (= no-slip). (implicitly)

But what about the square cylinder in the middle of the channel ? The grid in the channel was generated using the simple a block geometry with a uniform grid. And the cells within the square cylinder was then deleted from the cell set.

Does I also have to put no-slip wall definitions onto the square cylinder walls or are these wall defined the same way as the walls of the channel ???

Thanks in advance.


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Old   October 20, 2000, 03:34
Default Re: Star-CD and BC.
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Any unspecified boundary is automatically assigned to region 0, which is by default a no-slip wall.

As your case is 2D, don't forget the symmetry boundaries on the sides.
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