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C4 = 1 for Moving Mesh

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Old   January 15, 2005, 01:31
Default C4 = 1 for Moving Mesh
  #1
Xobile
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Hello,

I have run a moving mesh problem for 300 time steps keeping C4 = 1 which means it will not take into account the physical and material properties and will do a moving mesh on the geometry.

The simulation ran like shown below

|------------------------------------| I--------------------------------------------------| CALCULATION MONITORING INFORMATION |-------------------------------------------I

|------------------------------------|

TIME I----------------- GLOBAL ABSOLUTE RESIDUAL -----------------I I------------ FIELD VALUES AT MONITORING LOCATION ----------I

STEP UMOM VMOM WMOM MASS T EN DISS ENTH U V W P TE ED T

1

2

3

4

5

6

7

8

9

But when i want to see the moving mesh post processing using load data and time steps , for transient moving mesh case, none of the 300 time steps show up.

It looks all empty and so I dont know how to see the moving mesh results for transient case.

When I want to load steady state result (*.pst) the window closes sending everything to "core"

How to get this problem fixed??

Thanks

Xobile
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Old   January 15, 2005, 06:43
Default Re: C4 = 1 for Moving Mesh
  #2
Jörn Beilke
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It's a prostar bug in the newer versions. Just open prostaw without connecting the event file. Load the *.pst and do a "getv coor" to store the new vertex positions.

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Old   January 18, 2005, 06:22
Default Re: C4 = 1 for Moving Mesh
  #3
Narmin B
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In transient tab, you have to specify the solution to post not print.
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