How to use 1D profile data as 360° Inlet profile?

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 July 16, 2012, 11:01 How to use 1D profile data as 360° Inlet profile? #1 Member   don lenardo Join Date: Nov 2010 Posts: 75 Rep Power: 7 Hello, I want to use a 1D velocity profile along a line (r,u,v,w) as a 360° INLET boundary for an other case? Is it possible to "rotate" this 1D profile data by 360° to get a full 360° boundary field? Thanks in advance. Markus

 July 16, 2012, 12:50 #2 Senior Member     Alex Join Date: Jun 2012 Location: Germany Posts: 1,266 Rep Power: 22 Use a cylindrical coordinate system.

 July 16, 2012, 14:11 #3 Member   don lenardo Join Date: Nov 2010 Posts: 75 Rep Power: 7 I have only the Velocity components u,v,w at one's disposal along the line (that means u,v,w along the radius r). If I use this input profile in cyclindrical coordinate frame (Axial component = Line 1.Velocity u(r), Radial component = Line 1.Velocity v(r),Thetacomponent = Line 1.Velocity w(r) ), the inlet profile displayed by vectors does not match with the original one! That's clear because u is indeed equal to the axial component but v is not euqal to the radial component and w is not equal to the theta component (in my case with the exception of the y axis with z = 0). Or do anyone know, how to transform all these cartesian values into cyclindrical one in cfx?! Any other ideas?

 July 16, 2012, 16:06 #4 Senior Member     Alex Join Date: Jun 2012 Location: Germany Posts: 1,266 Rep Power: 22 It should be possible to transform the coordinates of a cartesian coordinate system into a cylindrical one and the other way round. http://en.wikipedia.org/wiki/Cylindr...rdinate_system The transformation doesn't need to be done in CFX, you can use Matlab, Excel or whatever suits you.

 July 16, 2012, 17:01 #5 Member   don lenardo Join Date: Nov 2010 Posts: 75 Rep Power: 7 Yes,the transformation is comprehensible for me but laborious as well. Therefore, I hoped that there is a transformation possible in cfx. OK, if there is no chance for transforming I am going to consider about another approach. Thanks

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