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symmetry and wall (free slip) BC

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Old   October 11, 2012, 03:10
Default symmetry and wall (free slip) BC
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Hamed Abdul Majeed
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Hi,
What is the difference between symmetry and free slip wall boundary conditions in ANSYS CFX.
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Old   October 11, 2012, 05:56
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This is described in the documentation.

Symmetry enforces zero normal gradient to all parameters, and a slip wall does not necessarily do this. But for most normal simulations they are equivalent.

And a symmetry plane is required to be planar, but a slip wall can be any shape.
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Old   August 20, 2015, 13:31
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@ghorrocks : Some body showed a case of cylindrical shape domain and he has applied symmetry condition for the 60 deg sector. In my understanding symmetry condition reflect the solution around the mirror plane which in my understating can only be applied to two planes in 3-d case. I suggested him the periodic bc instead.

What do you think?
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Old   August 20, 2015, 13:47
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I did not double-check if this is true in CFX. Another difference between the two boundary types should show up when using a turbulence model.
Near a free-slip wall, the turbulence kinetic energy is zero while at a symmetry boundary condition its normal gradient is zero.
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Old   August 20, 2015, 13:54
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Quote:
Originally Posted by flotus1 View Post
I did not double-check if this is true in CFX. Another difference between the two boundary types should show up when using a turbulence model.
Near a free-slip wall, the turbulence kinetic energy is zero while at a symmetry boundary condition its normal gradient is zero.
If any boundary (wall) is not generating turbulence, will it affect ?? in that case both will behave in similar manner?

This is taken from CFX help :

Quote:
For turbulent flows, the specified shear is applied directly; no considerations about turbulent wall functions are taken into account.
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Old   August 20, 2015, 14:02
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and this is from the fluent help (same meaning as shown in CFX help ) and which is very much clear...



Fluent help on symmetry BC:

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Old   August 20, 2015, 18:16
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Quote:
In my understanding symmetry condition reflect the solution around the mirror plane which in my understating can only be applied to two planes in 3-d case. I suggested him the periodic bc instead.
A symmetry boundary has zero normal flow. So that means no swirl. A periodic boundary allows normal flow so can allow swirl.

That is the key difference to keep in mind for symmetry versus periodic.
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