CFD Online Logo CFD Online URL
www.cfd-online.com
[Sponsors]
Home > Forums > Software User Forums > ANSYS > CFX

Cf and Cvp Contributions to Cd Using CEL

Register Blogs Community New Posts Updated Threads Search

Reply
 
LinkBack Thread Tools Search this Thread Display Modes
Old   May 19, 2005, 10:40
Default Cf and Cvp Contributions to Cd Using CEL
  #1
James Date
Guest
 
Posts: n/a
Hi

I'm sure this is straight forward and I'm just missing something. I know that when CFX-5.7.1 completes solving the integrated viscous and pressure forces are output in the .out file in the X, Y & Z coordinate directions. The total drag on the body is hence the sum of the viscous and pressure forces acting on the body.

Is there a command in post which will allows the user to output the viscous or the pressure contributions of force, rather than just their sum using "force_x()@body)". Or do I have to write an expression which sums the tangential shear force around the body to give the viscous drag?

James
  Reply With Quote

Old   May 19, 2005, 18:38
Default Re: Cf and Cvp Contributions to Cd Using CEL
  #2
Glenn Horrocks
Guest
 
Posts: n/a
Hi James,

I think you are right. To split the force into pressure and shear components you will have to integrate over the boundary surface.

Of course in CFX this is quite easy, a CEL expression something like:

Pressure Force = areaInt(p)@Surface

and

Shear Force = areaInt(Wall Shear)@Surface

Should do the trick.

Regards, Glenn Horrocks
  Reply With Quote

Old   May 20, 2005, 07:56
Default Re: Cf and Cvp Contributions to Cd Using CEL
  #3
James Date
Guest
 
Posts: n/a
Glenn Cheers for the advice, i figured that was probably the best way to do it. The commands i used in the end were:

X-Viscous force = areaInt(Wall Shear X)@body

Y-Viscous force = areaInt(Wall Shear Y)@body

Z-Viscous force = areaInt(Wall Shear Z)@body

X-Pressure force = areaInt(Pressure*Normal X)@body

Y-Pressure force = areaInt(Pressure*Normal Y)@body

Z-Pressure force = areaInt(Pressure*Normal Z)@body

Out of interest i checked the CEL computed values with those given in the .out file and guess what, there was a maximum of 10% difference in the values espically in the X component of pressure force (with the CEL giving the smallest value)! So which values are correct?

Any ideas?

James
  Reply With Quote

Old   June 8, 2005, 11:10
Default Re: Cf and Cvp Contributions to Cd Using CEL
  #4
Nepal
Guest
 
Posts: n/a
Hi, I think maybe there're something wrong,

<font color="blue">X-Pressure force = areaInt(Pressure*Normal X)@body</font> I think it should be: <font color="blue"> X-Pressure force = areaInt_x(Pressure)@body </font> I think your equation means: integral[(<font color="red">pressure fraction on X direction</font> * Area)] But the force should be integral[(pressure * area)*fraction_x]
  Reply With Quote

Old   June 8, 2005, 12:15
Default Re: Cf and Cvp Contributions to Cd Using CEL
  #5
Rui
Guest
 
Posts: n/a
Hi,

I think that <font color="blue">areaInt(Pressure*Normal X)@body</font> is exactly the same as <font color="blue">areaInt_x(Pressure)@body</font>

From CFX-5.7.1 documentation about <font color="blue">areaInt</font>: "If a direction is selected, the result is an integration over the projected area of each face onto a plane normal to that direction.""Function: areaInt, Location: Plane1, Variable: Pressure, Direction:X. This example integrates Pressure over the projected area of Plane1 onto a plane normal to the X-axis. The result is the Pressure force acting in the X-direction on Plane1."

Regards,

Rui
  Reply With Quote

Old   June 8, 2005, 19:04
Default Re: Cf and Cvp Contributions to Cd Using CEL
  #6
Nepal
Guest
 
Posts: n/a
Hi Rui,
I create a sphere inside a cube to test it.

1-areaInt_x(Pressure)@body=<font color="blue">0.00361582 N</font>
2-areaInt(Pressure*Normal X)@body=<font color="blue">0.00362184 N</font>
3-If I use calculater icon in CFX571,
function :areaInt
location :body
variable :Pressure
Direction:GLobal X
Then the result is 0.00361582

So I think for NormalX case, its area is not projected onto the direction X, its value is larger always. I'm not so sure that I'm right. I think it worth to paying more attention to make it clear for correct report.

Regards,
  Reply With Quote

Reply


Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Trackbacks are Off
Pingbacks are On
Refbacks are On



All times are GMT -4. The time now is 18:30.