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Old   September 11, 2007, 10:46
Default FSI-time dependent load in cfx10.0
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hello, i am working on a fsi simulation in cfx10.0.load is a pressure like "sin 5t".(t is time) but cfx in post processing doesn't accept can i apply this load?should i write a fortran program?can anyone guide me? thanks.
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Old   September 12, 2007, 05:12
Default Re: FSI-time dependent load in cfx10.0
V. Kumar
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How can you define loads in CFX-POST? In order to define load or a boundary condition (B.C) you have to go either to ANSYS or CFX-PRE. If it is load on the structure you can edit your ANSYS input like following under /SOLU or /PREP7:


nsel,s,..... !!with nsel select you nodes where you want to apply time-dependent load

*dim, press,table,100,1 !define a variable array e.g. press of length 100

delt=1e-4 !define size of time-step

FREQ=10 !define freqency e.g. 10 Hz

pi = 4*atan(1) ! define your Pi or pi = 3.14157

omega = 2*pi*FREQ

p_max = 10 ! amplitude of the load





SF,all,PRES,%press% ! apply pressure load vector on selected nodes


If you want to apply a B.C on the fluid side, this can be done in CFX-PRE. In CFX-PRE a time-dependent B.C can be set by CEL which is quite easy using variable "t". Refer to CFX manuals for this.

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Old   September 15, 2007, 10:28
Default Re: FSI-time dependent load in cfx10.0
siavash ghassemi
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as you wrote i could apply a time dependent b.c in cfx-pre with no error.("sin t" as a mesh displacement in y direction).but when i want to obtain a solution in cfx-solver(start run) an error massage displays that "t is not an angle"! how can i solve this problem? thanks, s.ghassemi
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Old   September 16, 2007, 03:28
Default Re: FSI-time dependent load in cfx10.0
V. Kumar
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ofcourse "t" is not an angle.

Here is an example:

pi = 4*atan(1)

freq = 100 [s^-1]

theta = 2 * pi * freq * t

disp = 0.01 [m] sin(theta)

this should work.

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