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October 20, 2010, 13:05
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Expression for.....mod function
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#1 |
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New Member
Arvind
Join Date: Mar 2009
Posts: 13
Rep Power: 17  |
Hi everyone,
I have a simple question ...how to make expression for |a+b| or mod(a+b) using CFX Expression Language? Thank You Regards Arvind |
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October 20, 2010, 14:12
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#2 |
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New Member
ousegui
Join Date: Oct 2010
Posts: 19
Rep Power: 15 |
for |a+b| you write simply abs(a+b), but make sur that a and b have the same unity
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October 20, 2010, 18:16
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#3 |
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Super Moderator
Glenn Horrocks
Join Date: Mar 2009
Location: Sydney, Australia
Posts: 17,703
Rep Power: 143 |
And mod is mod(a+b). Not very difficult, is it?
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