# anisotropic material in CFX R13.0

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 March 13, 2013, 09:16 #21 New Member   endacid Join Date: Apr 2012 Posts: 1 Rep Power: 0 as serezhkin write it's working.Thanks! But keep in mind that the properties will work only reffered to the Coord 0.

October 16, 2016, 09:25
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 Originally Posted by serezhkin In case anyone still needs this, here's the ccl I received from ANSYS customer support: LIBRARY: &replace MATERIAL: Anyso Material Group = User Option = Pure Substance Thermodynamic State = Solid PROPERTIES: Option = General Material EQUATION OF STATE: Density = 2.645E3 [kg m^-3] Molar Mass = 1 [kg kmol^-1] Option = Value END REFERENCE STATE: Option = Specified Point Reference Specific Enthalpy = 0 [J kg^-1] Reference Temperature = 25 [C] END SPECIFIC HEAT CAPACITY: Option = Value Specific Heat Capacity = 1.36E3 [J kg^-1 K^-1] END THERMAL CONDUCTIVITY: Option = Orthotropic Cartesian Components Thermal Conductivity X Component = 0.001 [W m^-1 K^-1] Thermal Conductivity Y Component = 500 [W m^-1 K^-1] Thermal Conductivity Z Component = 5 [W m^-1 K^-1] #Thermal Conductivity = 175 [W m^-1 K^-1] AXIS DEFINITION: Option = Coordinate Axis Rotation Axis = Coord 0.3 END END END END END
Hi, regarding post number #11 in this thread:

Here, the thermal conductivity has been defined in x,y and z direction, respectively. But why again thermal conductivity is defined in # statement? Is it average thermal conductivity? If so average is 168.33 [W m^-1 K^-1] and not 175 175 [W m^-1 K^-1].

I am facing same issue, in which I have use a solid material in cfx which is an-isotropic considering varying thermal conductivity in x,y,z.

To quote #11
" THERMAL CONDUCTIVITY:
Option = Orthotropic Cartesian Components
Thermal Conductivity X Component = 0.001 [W m^-1 K^-1]
Thermal Conductivity Y Component = 500 [W m^-1 K^-1]
Thermal Conductivity Z Component = 5 [W m^-1 K^-1]
#Thermal Conductivity = 175 [W m^-1 K^-1] "

 October 16, 2016, 18:52 #23 Super Moderator   Glenn Horrocks Join Date: Mar 2009 Location: Sydney, Australia Posts: 12,720 Rep Power: 99 As this is an undocumented feature I don't think anybody will know the answer to your question. Unless you have access to the CFX source code..... So the only way to find out is to test to see what it does. Do a simple demonstration simulation using anisotropic thermal conductivity, and then repeat it using 10x the isotropic thermal conductivity and see if it makes any difference. The isotropic thermal conductivity may well be ignored by the solver but it is required so the check for the necessary parameters to define the run are present. But that is just a guess.

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