CFD Online Logo CFD Online URL
www.cfd-online.com
[Sponsors]
Home > Forums > CFX

Symmetry

Register Blogs Members List Search Today's Posts Mark Forums Read

Reply
 
LinkBack Thread Tools Display Modes
Old   May 22, 2011, 07:26
Default Symmetry
  #1
New Member
 
Saravanakumar
Join Date: Apr 2010
Location: Bangalore
Posts: 9
Rep Power: 7
saravana is on a distinguished road
Hi All,

I need to do cfx simulation for Impellar type fuel pump.
It has five domains.
1. Inlet Domain (unsymmetry)
2. Axial Clearance - Inlet side Domain (symmetry)
3. Blades Domain (35 fluid blade volumes spread out for 360)
4. Axial clearancee - Outlet side Domain (symmetry)
5. Outlet Domain (unsymmetry)

Both in the top and bottom extreme (Inlet and outlet Domain) is circular sector volume and is not a symmetric geometry.
Next to those domains is axial clearances, which is a symmetric (complete circular volume) Domain.
In between these axial clearances, 35 impeller blade fluid volumes spread out for comple 360.

My question here is that, is it possible to simplify the model with only one blade instead of complete 35 blades, considering the fact that the domains these blades is going to have domain interface (Axial clearances) is uniform for 360. But the other two domains (inlet & Outlet) are not symmetry.

Please give your suggestions.

Saravana
saravana is offline   Reply With Quote

Old   May 22, 2011, 07:33
Default
  #2
Far
Super Moderator
 
Far's Avatar
 
Sijal Ahmed Memon (turboenginner@gmail.com)
Join Date: Mar 2009
Location: Islamabad Pakistan
Posts: 3,905
Blog Entries: 6
Rep Power: 38
Far will become famous soon enoughFar will become famous soon enough
Send a message via Skype™ to Far
Quote:
But the other two domains (inlet & Outlet) are not symmetry.
But It has the periodicity ever where, use periodic condition at the interface between two blades
Far is offline   Reply With Quote

Old   May 22, 2011, 10:11
Default Symmetry
  #3
New Member
 
Saravanakumar
Join Date: Apr 2010
Location: Bangalore
Posts: 9
Rep Power: 7
saravana is on a distinguished road
Thanks for your reply Mr.Far.

There will be no interface between blades.
There will be interface between blades and axial clearances in both top and bottom directions.
My dought is that, to have periodicity, do we need to have all the domains symmetry?

Saravana
saravana is offline   Reply With Quote

Old   May 22, 2011, 12:15
Default
  #4
Far
Super Moderator
 
Far's Avatar
 
Sijal Ahmed Memon (turboenginner@gmail.com)
Join Date: Mar 2009
Location: Islamabad Pakistan
Posts: 3,905
Blog Entries: 6
Rep Power: 38
Far will become famous soon enoughFar will become famous soon enough
Send a message via Skype™ to Far
that is imaginary interface or plane created by the CFD user. This plane is approximately between two blades and then same is copied to other side of blade by the angle 360/35 (for your case) and then we give them periodic condition in CFX pre. In this way you have to only solve one passage and get the solution for whole impeller
Far is offline   Reply With Quote

Old   May 22, 2011, 15:52
Default
  #5
Far
Super Moderator
 
Far's Avatar
 
Sijal Ahmed Memon (turboenginner@gmail.com)
Join Date: Mar 2009
Location: Islamabad Pakistan
Posts: 3,905
Blog Entries: 6
Rep Power: 38
Far will become famous soon enoughFar will become famous soon enough
Send a message via Skype™ to Far
can you please post pic of impeller
Far is offline   Reply With Quote

Reply

Thread Tools
Display Modes

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Trackbacks are On
Pingbacks are On
Refbacks are On


Similar Threads
Thread Thread Starter Forum Replies Last Post
[ICEM] Blocking and Symmetry BrolY ANSYS Meshing & Geometry 32 August 24, 2012 03:13
Properly using symmetry with both CFX and ANSYS workbench for a FSI analysis, help! Cirion0000 CFX 0 July 6, 2009 14:26
Forces in Symmetry Matt CFX 2 February 25, 2009 06:41
Symmetry plane error in solver Santiago Orrego. CFX 6 January 31, 2007 08:09
4 symmetry BC in a cuboid Ralf Schmidt FLUENT 0 November 1, 2006 17:29


All times are GMT -4. The time now is 01:14.