# Combination of simple Photometric and CFD analysis

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June 29, 2011, 03:47
Combination of simple Photometric and CFD analysis
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Dmitry
Join Date: Jun 2011
Posts: 4
Rep Power: 6
Brief description of a problem.
I have very simple chemical reactor with water flow lighted by flash lamps. (see pic.). There is numerous of small bodies inside the flow. I'm modeling energy absorbed (doze) by this bodies during passing the reactor. My task is to improve geometry of the reactor to increase the doze.

I ask for advice for modeling the light source. During modelling I find very strange result for doze, there was no big difference how far from the light source small body is. I have create simple model (pic 2) several spheres one of them was source of radiation. I see all the spheres absorb equal energy, but the distance between them was different.

I use Discrete Transfer model. Radiation source is isotropic. Absorption is measured by using Absorbed Radiation Flux function.

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 June 29, 2011, 06:45 #2 Super Moderator   Glenn Horrocks Join Date: Mar 2009 Location: Sydney, Australia Posts: 10,805 Rep Power: 85 If the outer wall is reflective then the radiation will be uniform and no matter where it is it will get the same dose. What is your outer wall boundary condition for radiation?

 June 29, 2011, 08:35 #3 New Member   Dmitry Join Date: Jun 2011 Posts: 4 Rep Power: 6 Boundary condition for wall: Wall Emissivity - 0 Diffuse fraction - 1 But in my second model (pic.2) I expected to see inverse-square law, because there is no any walls except spheres, all others was opening(material - air).

 June 29, 2011, 08:44 #4 Super Moderator   Glenn Horrocks Join Date: Mar 2009 Location: Sydney, Australia Posts: 10,805 Rep Power: 85 But what radiation condition did you apply to the opening? I think you want to apply 0K blackbody temp so no radiation comes back from the opening.

 June 29, 2011, 09:11 #5 New Member   Dmitry Join Date: Jun 2011 Posts: 4 Rep Power: 6 Thank you for idea with blackbody temperature at the opening, I've forgot about it.

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