Total pressure in rel frame and total pressure
Hi! Please let me know what is a principal difference between Total pressure in rel frame and Total Pressure functions in a case of axial turbine stage problem. CFX Post returns different fields of theese variables on turbo surface with constant span =0.5, but i think they must be identical. Thanks.

Total pressure = p + 1/2 rho v^2
The velocity term is different depending on what frame of reference you measure it in. This means total pressure is different in different frames of reference. 
Thanks, ghorrocks. I was made a mistake in my question, in fact I told about only rotating domain. The velocity term on the rotating frame of reference is the same for total pressure and total pressure in rel frame, isn't it? So why do the total pressure and total pressure in rel frame fields for look different in a same rotating domain?

My previous post explains why. Because the velocity in the two frames of reference is different.

Ok, probably it's my english problems.
I ask you directly: What is the differnce between: Total Pressure in Stn Frame=p+1/2*rho*Ustn^2 (1) Total Pressure in Rel Frame=p+1/2*rho*Urel^2 (2) Total Pressure = p+1/2*rho*(Urel^2(omega*R)^2) (3) I know, that Urel=Ustnomega*R in rotating systems, Physical meaning of 1 term  absolute total pressure Physical meaning of 2 term  relative total pressure But what's the physical meaning of term 3 ????!!!! Best wishes! 
Eqn 3 is not total pressure. It is rothalpy. Look it up in the documentation (eqn 156 in the theory guide) or on google.

Quote:
Total pressure in rotating frame is less than static pressure (In the outlet ), whereas according to equation: Total Pressure in Rel Frame=p+1/2*rho*Urel^2, it should be greater than static pressure because of positive values of "1/2*rho*Urel^2" in any condition(rotating or stationary frame) . My test case is NASA rotor37. What is the reason for this contradiction? Another question: Urel=Ustnomega*R and Ptotal(rot)=pstatic+1/2*rho*Urel^2, as aresult: Ptotal(rot)=pstatic+1/2*rho*(Ustnomega*R)^2 but in cfx theory guide(equation 153): Ptot(rot)=Pstatic+1/2*rho*(Urel*Urel(omega*R.omega*R)). What is the reason for this contradiction? 
Are you saying you are getting total pressure in a rotating frame less than inlet static pressure in your case? Can you post an image of what you are modelling? And the boundary conditions?

1 Attachment(s)
Yes, In CFDPost, 3 Total pressure is exist: Total Pressure, Total pressure in Rel Frame and Total Pressure in stn Frame. Total pressure is less than static pressure but total pressure in rel frame and total pressure in stn frame is greater than static pressure. Image of Mach contour in 80% span is attached. Boundary condition:
Test case: NASA ROTOR 37 Reference pressure:0 [pa] Inlet: Total pressure:1[atm] Outlet: Static pressure:106.5 [kpa] Angular velocity:1800[rad/s] High resolution discretization is used for all equations. High speed numeric, clip pressure and high resolution rhio chow algorithm are activated via advance parameter tab in solution tab. I can not reach to nominal mass flow rate (20.19 kg/s) and total pressure ratio (2.1) by variation in static pressure. I reached to pressure ratio 1.88 and mass flow rate 20.38 at best condition. What is its solution? 
Hi guys,
I was reading the forum and have still a question regarding the total pressure in rotating frame. I could reproduce the values for "TotalPressure in relative and stationary frame" with the given formulas. But for the TotalPressure itself I didnt get the value in [Pa] as CFX gives me, I get to high values. Total Pressure in Stn Frame=p_stat+1/2*rho*Ustn^2 OK Total Pressure in Rel Frame=p_stat+1/2*rho*Urel^2 OK Total Pressure = p_stat+1/2*rho*(Urel^2(omega*R)^2) Fail For R I use the maxValue at the plane I want to investigate. Would be nice if someone could give me some advice. Thanks 
Rothalpy shows the loss without output work
Quote:
Difference between total pressure, total pressure in Stn and in Rel frames Anyhow, if you understand what rothalpy is, these three definitions of "total pressure" should not be a problem. The definiton of Total Pressure here, which is used in CFDPost, is deduced from rothalpy. It gets rid off the work which the fluid output against the rotors. The work will be computed differently in the stationary frame and rotational frame. If the stationary work is added to rothalpy, the result is the total enthalpy in stationary frame. And the difference between rothalpy and the total enthalpy in relative frame showes the effect of Coriolis force. The equation of rothalpy includes a part that (Omega X Radius)^2 should be taken away. So if the calculation is about rotors, and the output work is very large, it is quite possible that the rothalpy is negative, or the total pressure is less than the static pressure. I think this Total Pressure definition based on rothalpy can be very convenient for loss assessment, especially for the centrifugal pump or radial flow turbine. For these flowfields, the Omega X Radius may be quite different on the same streamline within a rotational domain. 

All times are GMT 4. The time now is 07:49. 