|March 17, 2012, 18:50||
momentum loss equation porous media
Join Date: Jan 2012
Posts: 31Rep Power: 6
i am modelating flow through a porous media as a simplification of a perforated difusser.
In order to obtain the same velocity profile as i did in the real perforated diffuser, i am taking different values for permeability coefficient and resistance loss coeffcient.
As far as i know, both of them define the mometum loss in the porous domain(both terms take part in the momentum loss equation), and hence the pressure drop.
would it actually be the same just changing one of these two parameters? could i get the same results by just changing one of them with a wide range of values?
is there actually any diffrenece between both of them? (i am refering to the effects on the porous media)
could anyone help me please?
|March 21, 2012, 19:28||
Join Date: Feb 2011
Location: Earth (Land portion)
Posts: 566Rep Power: 11
permeability is the linear part of the loss model. loss coefficient is the quadratic part. you can use either one or both, depending on the characteristics of your diffuser. Solver theory guide will give you the exact formula for each I cant remember of the top of my head, or can I.....
DeltaP = -(Viscosity * Velocity / K.perm) - (Density*Loss.Coefficient*Velocity^2)
units will be Pa/m
|Thread||Thread Starter||Forum||Replies||Last Post|
|How to model granular flow through porous media||Axius||FLUENT||2||August 7, 2014 10:34|
|Multiphase Porous Media Flow - Convergence Issues||VT_Bromley||FLUENT||5||March 23, 2011 11:38|
|porous media in CFX||X. Shen||CFX||2||September 4, 2010 06:46|
|spercritical fluid flow in porous media||cachen||FLUENT||3||November 10, 2007 03:20|
|Need help : porous media for heat exchanger||X. Shen||CFX||0||December 18, 2004 12:10|