Boundary Type for the rotation Axis in CFX-Pre

mk23 · March 20, 2012, 11:00

What type of boundary should i take for the rotation axis in a 2.5D model.

thank you very much for the help
PS: i use periodic interface for the both sides

ghorrocks · March 20, 2012, 16:17

Assuming by 2.5D by mean an 2D axisymmetric simulation with an out-of-plane swirl component, or a 2D planar simulation with an out-of-plane component - then this can be done using a periodic boundary.

mk23 · March 21, 2012, 07:43

thank you
but cfx-solve says there is no boundary at the xxx-position(where the rotation axis is). my question is which bounday should i select for the xxx(rotation axis)? symmetrie? free slip wall?

ghorrocks · March 21, 2012, 16:42

If your geometry is a wedge then you do not need to define any boundary at the rotation axis. CFX does not have linear boundary conditions, only surface boundary conditions. Can you post an image of your geometry?

March 20, 2012, 11:00	Boundary Type for the rotation Axis in CFX-Pre	#1
mk23 New Member Zhu Wentao Join Date: Jun 2010 Posts: 3 Rep Power: 15	What type of boundary should i take for the rotation axis in a 2.5D model. thank you very much for the help PS: i use periodic interface for the both sides

March 21, 2012, 07:43	but-...	#3
mk23 New Member Zhu Wentao Join Date: Jun 2010 Posts: 3 Rep Power: 15	thank you but cfx-solve says there is no boundary at the xxx-position(where the rotation axis is). my question is which bounday should i select for the xxx(rotation axis)? symmetrie? free slip wall?

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March 20, 2012, 16:17		#2
ghorrocks Super Moderator Glenn Horrocks Join Date: Mar 2009 Location: Sydney, Australia Posts: 17,703 Rep Power: 143	Assuming by 2.5D by mean an 2D axisymmetric simulation with an out-of-plane swirl component, or a 2D planar simulation with an out-of-plane component - then this can be done using a periodic boundary.

March 21, 2012, 16:42		#4
ghorrocks Super Moderator Glenn Horrocks Join Date: Mar 2009 Location: Sydney, Australia Posts: 17,703 Rep Power: 143	If your geometry is a wedge then you do not need to define any boundary at the rotation axis. CFX does not have linear boundary conditions, only surface boundary conditions. Can you post an image of your geometry?