Wing Lift and drag coefficient

thiez03 · April 15, 2012, 07:13

Hi everyone!!!

I am trying to calculate the lift and drag coefficient of a 3D wing in CFX. I know CFX offers viscous force in X, Y and Z direction.

My flow is aligned with the the x-axis. Therefore, am I right saying that I can use the force in the x-axis to obtain Cd and the force on the y-axis can be used to obtain Cl ??!!

Thank you for your consideration.

ghorrocks · April 15, 2012, 17:51

Quote:

I know CFX offers viscous force in X, Y and Z direction.

No, CFX gives the total force in X/Y/Z directions. It does not calculate viscous forces separately. But you may be able to calculate it from integrals of wall shear stress.

Your question is correct. This is the standard definition for Cd and Cl.

thiez03 · April 16, 2012, 09:26

Thank you so much!!

So basically the force in x-axis is also the drag force (skin friction + form drag etc.) and the y-axis is the amount of lift force produced by the wing.

From these forces I just have to work out, the Cl and Cd.

Thank you once more for your time

Kind Regards

ghorrocks · April 17, 2012, 01:18

That's right. force_x/y/z is the total force in that direction.

April 15, 2012, 07:13	Wing Lift and drag coefficient	#1
thiez03 New Member Thierry Chavagnan Join Date: Apr 2012 Posts: 6 Rep Power: 14	Hi everyone!!! I am trying to calculate the lift and drag coefficient of a 3D wing in CFX. I know CFX offers viscous force in X, Y and Z direction. My flow is aligned with the the x-axis. Therefore, am I right saying that I can use the force in the x-axis to obtain Cd and the force on the y-axis can be used to obtain Cl ??!! Thank you for your consideration.

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April 16, 2012, 09:26		#3
thiez03 New Member Thierry Chavagnan Join Date: Apr 2012 Posts: 6 Rep Power: 14	Thank you so much!! So basically the force in x-axis is also the drag force (skin friction + form drag etc.) and the y-axis is the amount of lift force produced by the wing. From these forces I just have to work out, the Cl and Cd. Thank you once more for your time Kind Regards

April 17, 2012, 01:18		#4
ghorrocks Super Moderator Glenn Horrocks Join Date: Mar 2009 Location: Sydney, Australia Posts: 17,700 Rep Power: 143	That's right. force_x/y/z is the total force in that direction.