# How to apply the temperature boundary condition on the outside of the mould?

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 May 19, 2010, 11:04 How to apply the temperature boundary condition on the outside of the mould? #1 New Member   Han Join Date: May 2010 Posts: 13 Rep Power: 7 Hi, All I am trying to simulate a simple sand casting process, in which hot melt flows in the cavity of the mould and cooling channel is applied on the outside of the mould. I would like to set the outside boundary of the mould a fixed temperature as a cooling condition, however, when I use “Model setup-Boundaries-Mesh Boundaries-Block-Wall or others”, it doesn’t work at all no matter what temperature I set. So my question is that how to apply the temperature boundary condition on the outside of the mould?

 May 21, 2010, 02:37 #2 Senior Member   Join Date: Mar 2009 Posts: 129 Rep Power: 8 you can set initial solid temperature for the mold under Meshing & Geometry -> Component -> Initial Conditions -> Temperature. But this is just an initial temperature for the solid object. For isothermal temp setting you may want to try Boundaries -> Wall -> Thermal Boundary Options -> Temperature. Hope this help.

May 21, 2010, 05:03
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New Member

Han
Join Date: May 2010
Posts: 13
Rep Power: 7
Quote:
 Originally Posted by ck5285 you can set initial solid temperature for the mold under Meshing & Geometry -> Component -> Initial Conditions -> Temperature. But this is just an initial temperature for the solid object. For isothermal temp setting you may want to try Boundaries -> Wall -> Thermal Boundary Options -> Temperature. Hope this help.
Yes, I just did that, but it didn't work.
The geometry is very simple, a rectagular mould with a cylinder cavity, I set the 4 sides of the mould as "wall" boundaries and change the temperature in the "thermal information", but the results didn't change at all even the wall temperature is unreasonable high or low.
I am so confused

 May 21, 2010, 11:51 #4 New Member   Han Join Date: May 2010 Posts: 13 Rep Power: 7 The Prepin data is as follows, in which the wall temperature is unreasonable, I just want to check if it works or not. Title This is a sample input file \$xput remark='units are ...', twfin=100., itb=1, ifenrg=2, iwsh=0, ihtc=2, ifsld=1, iedt=2, pltfrc=0.05, delt=1e-6, \$end \$limits \$end \$props rhof=2437., rhofs=2680., cv1=1194., cvs1=963., thc1=116.8, thcs1=152., clht1=3.89e+05, ts1=539.6, tl1=615.9, tniyam=-1., tsdrg=1., mui=0., mu1=0.0012, muc00=0., muc0=1., muc1=0., muc2=0., muc3=0., muc4=0., mutmp1=0., mutmp2=0., mutmp3=1., muthk=0., muthn0=0., muthn1=0., teut=0., cexf1=0., cstar=0., dratio=0., pcoef=0., fluid1='Aluminum Alloy A357', units='SI', \$end \$scalar \$end \$bcdata wl=2, wr=2, wf=2, wbk=2, wb=2, wt=5, pbct(1,6)=243.7, tbct(1,6)=620., tbct(1,1)=1e7, hwall1(1)=1e6, hwall2(1)=1e6, hwobs(1)=1e6, \$end \$mesh nxcelt=35, px(2)=0.8, nycelt=35, nzcelt=40, pz(2)=1.5, px(1)=-0.8, py(1)=-0.8, py(2)=0.8, pz(1)=-0.4, \$end \$obs avrck=-3.1, nobs=1, iob(2)=1, ioh(2)=1, xl(2)=-0.8, xh(2)=0.8, yl(2)=-0.8, yh(2)=0.8, zl(2)=-0.4, zh(2)=1.5, magnx(2)=1., magny(2)=1., magnz(2)=1., subcmpid(2)='Rectanguar', material(1)='Steel H-13', twobs(1,1)=294., kobs(1)=28.6, rcobs(1)=3.5618e+06, hobs1(1)=20000., hobs2(1)=-1., ocang(1)=90., obsid(1)='Moud and cavity', subcmpid(3)='Cylinder', iob(3)=1, ioh(3)=0, zl(3)=0., zh(3)=1.5, rah(3)=0.4, magn(3)=1., magnx(3)=1., magny(3)=1., magnz(3)=1., rotx(3)=0., roty(3)=0., rotz(3)=0., trnx(3)=0., trny(3)=0., trnz(3)=0., hobv1(1)=0., hobv2(1)=0., hobv3(1)=0., \$end \$fl \$end \$bf \$end \$temp \$end \$motn \$end \$grafic \$end &HEADER PROJECT='Rectangular', / \$parts \$end Documentation: general comments, background, expectations, etc. #start tables: #component(1): #end component(1) #fluid1: #end fluid1 #fluid2: #end fluid2 #end start tables

 May 24, 2010, 20:52 #5 Senior Member   Join Date: Mar 2009 Posts: 129 Rep Power: 8 strange i did try myself, it also didn't work out with V9.4.1. So anyone have this problem before?

 May 25, 2010, 05:32 #6 New Member   Han Join Date: May 2010 Posts: 13 Rep Power: 7 CK, I finally found the problem. Even I used a so high temperature and long cooling time, the heat transfer coefficient l used above was still not big enough, comparing to the distance between the heat source and the boundaries. Increase the thermal conductivity or shorten the distance of the boundaries, the boundary temperature will play a part.

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