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udf eror + Define property + density

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Old   August 29, 2011, 08:54
Smile udf eror + Define property + density
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hi,I want to assign a high density (infinity) to a region of my 2D model.
I have writen the following code;

#include "udf.h"
DEFINE_PROPERTY(cell_density, cell, thread)
{
real density;
real grid_y = NODE_Y(cell, threads);
real grid_x = NODE_X(cell, threads);
if ( grid_x >= 30. && grid_x <= 40. )
{
if ( grid_y >= 10. && grid_y <= 20. )
{
density =1000000000;
}
}
}


but I have received the following error:

line 5: macro `NODE_Y' used with too many (2) args

can anyone help me with it?
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Old   August 29, 2011, 09:24
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See the definition:

Code:
#define NODE_Y(v) (NODE_COORD(v)[1])
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Old   August 29, 2011, 09:36
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Hi,
you wouldn't need any UDF for this case; separate desired space and set different density.
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Old   August 29, 2011, 10:29
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hi,thanks for ur replying,you say true,but my teacher tell me that i should solve this problem with udf,please say me what i should to do?please write all of the udf(i am in the start of the writing udf)thanks
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Old   August 29, 2011, 10:45
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Quote:
Originally Posted by rezvan View Post
hi,thanks for ur replying,you say true,but my teacher tell me that i should solve this problem with udf,please say me what i should to do?please write all of the udf(i am in the start of the writing udf)thanks
Dear Rezvan,
for such cases, we use cell values instead of node ones. I didn't check this UDF; check 2 rho vales:
Code:
#include "udf.h"
DEFINE_PROPERTY(my_density, c, t)
{
real rho;
real cr[ND_ND];
C_CENTROID(cr,c,t);
if ( cr[0] >= 30. && cr[0] <= 40. && cr[1] >= 10. && cr[1] <= 20.)
{
rho =1000000000;
}
else
{
rho=1.0; //check that
}
return rho;
}
Bests,
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Old   August 29, 2011, 20:56
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hi,i am really thank you,i take a lot of ur time,exuse me,when i interpreted this udf,acure this eror:
line 1: parse error.
plz help me
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Old   August 29, 2011, 20:58
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dear fox000002 ,hi,thank u a lot,i am in the start of writting udf,plz SITUATION your sentence in my udf
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Old   August 30, 2011, 04:45
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Quote:
Originally Posted by rezvan View Post
hi,i am really thank you,i take a lot of ur time,exuse me,when i interpreted this udf,acure this eror:
line 1: parse error.
plz help me
Hi,
I checked that both as interpreted and compiled one and there is not any error!
maybe there is a problem in your text editor. use this attached file.

Bests,
Attached Files
File Type: c density.c (232 Bytes, 50 views)
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Old   August 30, 2011, 06:43
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hi,thank u a lot...with ur help,my problem solved,bud if u have time ,i am glading that u answer to my other guestions :
1=this program must be .h or .c ?
2=in this udf whats the meaning and aplication of these words:
("real" and "rho" and "cr[ND_ND] and "C_CENTROID(cr,c,t)"
3=and my importand guestion is that :
why u answer to my guestions and other guestion of every peaple ?and spend alot of ur time for me & others?

Last edited by rezvan; August 30, 2011 at 07:21.
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Old   August 30, 2011, 08:12
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Quote:
Originally Posted by rezvan View Post
hi,thank u a lot...with ur help,my problem solved,bud if u have time ,i am glading that u answer to my other guestions :
1=this program must be .h or .c ?
this is a main program part which includes execution macro and should be stored in .C extension; .H extension are header files which are generally consist of class definitions such as udf.h. for more info, it's better to refer to C or C++ documentations.
Quote:
Originally Posted by rezvan View Post
2=in this udf whats the meaning and aplication of these words:
("real" and "rho" and "cr[ND_ND] and "C_CENTROID(cr,c,t)"
real-> type definition(float); it's a class
rho-> just a name; it's an object in real class
cr[ND_ND]-> self adjusting dimension array in 2D or 3D solvers; i.e., in 2D it's cr[2] and in 3D it's cr[3]
C_CENTROID(cr,c,t)-> it stores center cell coordinate of cell index c which belongs to thread t in array cr
Quote:
Originally Posted by rezvan View Post
3=and my importand guestion is that :
why u answer to my guestions and other guestion of every peaple ?and spend alot of ur time for me & others?
I'll be glad if I can help others; in this forum, you can improve your CFD knowledge regardless that you ask a question or answer that. Many questions don't take much time; like yours.

Bests,
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