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vibhs August 21, 2012 00:34
hydraulic diameter
 
With reference to Fluent tutorial no. 1: Fluid flow and heat transfer in mixing elbow, could someone plz expalin me how the hydraulic diameter of an elbow in 2-D is 32", which has its width to be 16"?

eng_s_sadeghi August 21, 2012 03:35
Hydraulic diameter = 4A/P
A= pi*r^2
P= 2*pi*r

vibhs August 21, 2012 05:36
Quote:
Originally Posted by eng_s_sadeghi (Post 377917)
Hydraulic diameter = 4A/P
A= pi*r^2
P= 2*pi*r
Its a 2-d problem. i dont have any "r" value. I just have one dimension of the elbow i.e. 16".

eng_s_sadeghi August 21, 2012 05:40
In this case, width of the channel is your hydraulic diameter.

vibhs August 21, 2012 05:46
Quote:
Originally Posted by eng_s_sadeghi (Post 377946)
In this case, width of the channel is your hydraulic diameter.
hydaulic diameter taken is 32". You can cross check in the first tutorial of the fluent...:confused:...I am confused

eng_s_sadeghi August 21, 2012 05:54
Is it an axisymmetic 2D problem?
If yes, It's correct.

vibhs August 21, 2012 06:31
Quote:
Originally Posted by eng_s_sadeghi (Post 377950)
Is it an axisymmetic 2D problem?
If yes, It's correct.
How come?...Could you please explain?


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