# hydraulic diameter

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 August 21, 2012, 00:34 hydraulic diameter #1 New Member   vibhor goel Join Date: May 2012 Location: India Posts: 14 Rep Power: 5 With reference to Fluent tutorial no. 1: Fluid flow and heat transfer in mixing elbow, could someone plz expalin me how the hydraulic diameter of an elbow in 2-D is 32", which has its width to be 16"?

 August 21, 2012, 03:35 #2 Member     Join Date: Mar 2011 Posts: 64 Rep Power: 6 Hydraulic diameter = 4A/P A= pi*r^2 P= 2*pi*r __________________ Saeed Sadeghi Ansys Fluent CFD Consultant

August 21, 2012, 05:36
#3
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vibhor goel
Join Date: May 2012
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Quote:
 Originally Posted by eng_s_sadeghi Hydraulic diameter = 4A/P A= pi*r^2 P= 2*pi*r
Its a 2-d problem. i dont have any "r" value. I just have one dimension of the elbow i.e. 16".

 August 21, 2012, 05:40 #4 Member     Join Date: Mar 2011 Posts: 64 Rep Power: 6 In this case, width of the channel is your hydraulic diameter. __________________ Saeed Sadeghi Ansys Fluent CFD Consultant

August 21, 2012, 05:46
#5
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vibhor goel
Join Date: May 2012
Location: India
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Quote:
 Originally Posted by eng_s_sadeghi In this case, width of the channel is your hydraulic diameter.
hydaulic diameter taken is 32". You can cross check in the first tutorial of the fluent......I am confused

 August 21, 2012, 05:54 #6 Member     Join Date: Mar 2011 Posts: 64 Rep Power: 6 Is it an axisymmetic 2D problem? If yes, It's correct. __________________ Saeed Sadeghi Ansys Fluent CFD Consultant

August 21, 2012, 06:31
#7
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vibhor goel
Join Date: May 2012
Location: India
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Quote:
 Originally Posted by eng_s_sadeghi Is it an axisymmetic 2D problem? If yes, It's correct.