
[Sponsors] 
October 23, 2012, 11:58 
Volume flow rate through actuator disk (Tidal turbine)

#1 
Member
Join Date: Jan 2011
Posts: 42
Rep Power: 7 
Hi,
I´m modelling an array of 3 marine current turbines using a porous jump boundary condition. The domain is a rectangular channel with 650. length, 400m width and 100m depth. Hub height is 30m from the bottom. Porous jump parameters are the same for the 3 turbines and are set to represent a thrust coeff. = 0.8. Parameter values are:  Face permeability, m²: 1e+10  Porous medium thickness, m: 0.5  Pressure Jum Coeff. C2, 1/m: 25 Solution converges after 260 iterations. Follows a figure showing velocity magnitude contours at hub height horizontal plane. When I generate the reports for Volumetric and Mass Flow Rates for each turbine, I get negative values for side turbines and a positive value for center turbine. Values are as follows: Volumetric Flow Rate (m3/s)   (Up) Turbine1 37.982517 (Center) Turbine2 90.828041 (Down) Turbine3 38.849861   Net 13.995665 Mass Flow Rate (kg/s)   (Up) Turbine1 38932.082 (Center) Turbine2 93098.742 (Down) Turbine3 39821.109   Net 14345.555 But surface velocity integral are very similar for each disk. Does anyone knows why this is happening and how can I obtain real values? Thanks in adavance. 

August 11, 2013, 15:49 

#2 
New Member
Derek Foran
Join Date: Jul 2013
Posts: 10
Rep Power: 4 
Hi,
I was wondering how you managed to figure out the required pressure jump c2 coefficient of 25? I am modelling a similar tidal turbine problem and not sure what the appropriate porous jump parameters would be to model a turbine with 35% efficiency. Thanks! Derek 

August 12, 2013, 10:27 

#3 
Member
Join Date: Jan 2011
Posts: 42
Rep Power: 7 
Hi Derek,
The values of C2 = 25/m and a porous medium thickness of 0.5m are incorrect. I took thos values from a scientific paper, but now I disagree. The best way to calculate C2 is using actuator disk theory. In order to do the calculations you need to assum some initial values like, free stream velocity, power coefficient and medium thickness. The procedure will be: 1  For a given power coefficient you can find out the related axial induction factor, a. 2  With a you get the velocity at the wake, Uw. Uw = Uo(12a). 3  Knowing the free stream velocity and wake velocity you calculate the pressure jump. 4  Finally, with the pressure difference at both sides of the disk you can apply equation 7.369 (http://www.sharcnet.ca/Software/Flue...ug/node256.htm) and calculate C2. Note that the velocity in equation 7.369 corresponds to the flow velocity at the disk, Ud, Ud = Uo(1a). Once you do the run with Fluent you can check your result. By applying this methodology I get a difference with teory of 4.4%. I hope I've helped you. Regards, Eduardo 

August 12, 2013, 12:24 

#4 
New Member
Derek Foran
Join Date: Jul 2013
Posts: 10
Rep Power: 4 
Thanks Eduardo this is great! Really appreciate the help


August 12, 2013, 15:18 

#5 
New Member
Derek Foran
Join Date: Jul 2013
Posts: 10
Rep Power: 4 
Hi Eduardo,
After calculating using the steps you gave me I got a c2 value of 0.5 with assumed thickness of 1 m. Is this within a similar range to the value you found? Thanks Derek 

Thread Tools  
Display Modes  


Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
Mass flow rate: calculation v/s computation  beguxa  FLUENT  4  June 8, 2013 16:17 
mass flow inlet and pressure outlet with target mass flow rate  Zigainer  FLUENT  10  January 5, 2013 22:51 
volume flow rate error in udf  jjchristophe  Fluent UDF and Scheme Programming  1  July 13, 2010 04:23 
mass flow in is not equal to mass flow out  saii  CFX  2  September 18, 2009 08:07 
tidal flow simulation using finite volume method  Jason Qiu  Main CFD Forum  0  October 20, 2002 02:34 