|
[Sponsors] |
May 7, 2013, 11:25 |
Heat Distribution
|
#1 |
New Member
Join Date: Jul 2012
Posts: 18
Rep Power: 13 |
Hi there,
I'm trying to implement heat flux lines on fluent. I'm new at UDF but I think I'm quite close to achieve this. I know that the heat distribution can be seen through temperature distribution, because they are penpendicular between each other, but i could't obtain them by only using temperature gradients. Does anybody know why? In the first picture, I tried to implement the equation: H= parte 1.jpg But the result should be something like this: como deveria ser.jpg When I tried to use only the temperature gradient, this is what I got: gradiente.png Any suggestions? |
|
|
|
Similar Threads | ||||
Thread | Thread Starter | Forum | Replies | Last Post |
mass flow in is not equal to mass flow out | saii | CFX | 12 | March 19, 2018 05:21 |
error message | cuteapathy | CFX | 14 | March 20, 2012 06:45 |
heat flux distribution | gtheo | CFX | 2 | April 27, 2011 03:36 |
Two-Phase Buoyant Flow Issue | Miguel Baritto | CFX | 4 | August 31, 2006 12:02 |
Convective Heat Transfer - Heat Exchanger | Mark | CFX | 6 | November 15, 2004 15:55 |