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-   -   heat exchanger with perforated fins ... help (https://www.cfd-online.com/Forums/fluent/133680-heat-exchanger-perforated-fins-help.html)

ayad April 18, 2014 12:36

heat exchanger with perforated fins ... help
 
Hi
I have cross flow finned tube heat exchanger with perforated annular fins as shown below.
http://s10.postimg.org/hhq4dfxih/Sna...BIT_Solver.png

after finishing the mesh and geometry and applied boundary condition by using GAMBIT i had exporting the case to fluent.
the problem, there is no connection between the duct and heat exchanger, in the other word the air doesn't collide with finned tube, so there is no stagnation and heat transfer.
Notes
1- constant temp. B.C applied to inner diameter of the pipe
2- the true result must be as shown in fig. below
http://s10.postimg.org/w9uu4s3ft/perforated_fin.jpg

ayad April 21, 2014 08:04

Really need help

ComputerGuy April 21, 2014 22:37

Sounds like you didn't subtract the inner part from the outer enclosure. Gambit won't automatically subtract the two in a boolean manner just because you set the boundary conditions appropriately. I would check your order of operations or, worst-case, post your journal file for us to review.

ComputerGuy

ayad April 22, 2014 09:21

thank u for your reply
subtract doesn't used here because i have no smooth pipe. I thing split volume must be used in my case. I used volume option to split the two volumes, Bidirectional and
connected options were selected, Retain option was unselected. is this right way please?

diamondx April 22, 2014 13:14

You need a Solid volume part and a FLUID volume. You need to ask how to do that in the meshing and the geometry section under the GAMBIT section.

ayad April 22, 2014 13:28

thank u for your reply
right
I do that, but there is no connection between (fluid and solid) volumes
I think the true result gained by use true method to split the two volumes.

diamondx April 22, 2014 13:36

of course between SOLID and FLUID, you need walls. I have no idea how to setup a mesh using GAMBIT... I wish i could help more

ayad April 22, 2014 13:42

Never mind, thank u so much

-mAx- April 28, 2014 01:36

Quote:

Originally Posted by ayad (Post 486913)
the problem, there is no connection between the duct and heat exchanger, in the other word the air doesn't collide with finned tube, so there is no stagnation and heat transfer.
Notes
1- constant temp. B.C applied to inner diameter of the pipe
2- the true result must be as shown in fig. below
http://s10.postimg.org/w9uu4s3ft/perforated_fin.jpg

can you post a picture of your problem for comparing with your perforated_fin.jpg

ayad April 28, 2014 03:02

Hi max thank u for your reply

http://s29.postimg.org/3l5knrjxj/Sna...22m49s_001.png
As you see there is no temp. variation in the air temp.

-mAx- April 28, 2014 03:06

I never did such computation, but I assume you have to handle thermal conduction within thin wall
check here:
https://www.sharcnet.ca/Software/Flu...e253.htm#33023

ayad April 28, 2014 03:28

Indeed i have select the Coupled option B.C. in the fluent .
I think the problem in the gambit, because there is no connection between the pipe and the duct. any method make a stagnation between fins and air will be solve the problem.

-mAx- April 28, 2014 03:38

do you have "shadow" walls?

ayad April 28, 2014 03:41

Yes, I have.

-mAx- April 28, 2014 03:46

are you coupling the good surface with its shadow surface?
if I see your picture you at least need 5 coupling

ayad April 28, 2014 03:51

No, I didn't do that.

-mAx- April 28, 2014 03:54

then what did you do?
display the list of your bc (wall and shadow) and explain what you did

ayad April 28, 2014 04:19

http://s23.postimg.org/5iojkoibv/Sna...02m21s_002.png


http://s2.postimg.org/6rwphkemh/Snap...ask_Page_A.png


firstly i specified two zones fluid zone (duct), and solid zone (pipe and fin).
then,
inter: fin surface area (coupled B.C.)
P: duct outlet (pressure outlet B.C)
S: Inner diam. of the pipe (constant temp. B.C.)
V: duct inlet (velocity inlet B.C)
WS: 4 wall of the duct
wall: I dont know why is appear

-mAx- April 28, 2014 04:27

*wall contains all outer surfaces on which you didn't set any BC, and Gambit set them automatically as wall

ok, now display the BC on inter and inter:012
and show me its geometry
(how did you set the BC? did you pick inter and inter:012 or only inter, then inter:012?)

ayad April 28, 2014 04:47

thank you for your time,and I'm sorry for delay, there is a problem in fluent because i connect the computer with internet, So i can't take a picture.
But, the fin and pipe surface area are the geometry of inter.
only inter gave B.C (coupled), and i had neglect inter:012.


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