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Free Surface Gravity Driven Flow

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Old   June 13, 2001, 15:12
Default Free Surface Gravity Driven Flow
  #1
Rupp Carriveau
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I am trying to solve a simple gravity driven funnel flow in Fluent. My mesh geometry is a simple cone, (upside down lampshade). I have specified that both the inlet and outlet have zero gauge pressure (both open to atmosphere)---(this flow is purely gravity driven). As this funnel drains I wish the water level to remain constant as if exactly what is drained is re-fed to the top. I have set the top and bottom of my cone as pressure inlet and outlets respectively, and set my cone structure simply as a wall. When I solve this flow the pressures vary so minutely from zero in between the 2 boundary conditions, and, velocity at the outlet is not even close to V=(2gh)^0.5, which it should at least be in the neighbourhood of. I have gravity turned on in the model, I checked most other things, can anyone suggest what I am missing in this simple problem?

Thanks so much,

Rupp.
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Old   June 13, 2001, 21:40
Default Re: Free Surface Gravity Driven Flow
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rafat
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Have you tried to apply body weighted coupling.
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Old   June 14, 2001, 15:03
Default Re: Free Surface Gravity Driven Flow
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Rupp
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Yes,

Results unfortunately remain unchanged.

Thanks for the response,

Rupp.
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Old   June 14, 2001, 16:53
Default Re: Free Surface Gravity Driven Flow
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Scott Whitney
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There is a small mistake in your logic. You forgot the pressure from the water on top of the bottom exit. For example if the funnel is 1m high, and the top inlet is set to 0 guage pressure, then the bottom outlet must be set to: density*gravity*height=-(1000kg/m^3)*(-9.81m/s^2)*(1m)=-9810 Pa guage

Note that gravity is negative in this case. I tried the solution and it works perfectly when the water pressure is included, but fails if both openings are set to the same pressure.
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Old   June 14, 2001, 16:54
Default Re: Free Surface Gravity Driven Flow
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Scott Whitney
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Oops, I put an extra negative sign accidently at the front of the formula. It should read:

density*gravity*height=(1000)*(-9.81)*1=-9810 Pa guage

Sorry about the typo.
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