# Need desperate help in convergence

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 August 1, 2002, 22:19 Need desperate help in convergence #1 Puck Guest   Posts: n/a I have a new problem now... I find that though my geometry is symmetrical(but im not using symmetrical planes) my solution looked weird when it converged.. there was no symmetry in the solution for heat transfer.. Therefore, i was asked to decrease the convergence criteria halfway through my iterations..i decreased all my parameters by 0.001 from the default values.. Now i find that those parameters which i decreased e.g z velocity is decreasing more than the criteria i input..The convergence criteria for all the parameters is around 10 to the power -5...meaning 0.000001.. But now the iterations show 0.00000001 and still havent converge.. I only set my energy as 10 to power -8..which is still in that range.. I stopped the iterations to see if my heat profile has symmetry; it has...So wht should i do? Assume the solution has converged? Plz help...

 August 2, 2002, 05:39 Re: Need desperate help in convergence #2 Erwin Guest   Posts: n/a Residuals are only one way of checking convergence, but they are not really what it is all about. You cannot specify a lower limit that residuals MUST adhere to, makes no sense. I have had problems with radiation in the past where the residuals did not change for a thousand iterations but the radiation fluxes kept on changing... So, look at your actual solution, if it looks okay (like have symmetry where you expect it) and if it doesn't change significantly during a number of iterations, then your solution is converged. Period.

 August 2, 2002, 09:58 Re: Need desperate help in convergence #3 Puck Guest   Posts: n/a Hi... thnx for replying... So u mean to say that, as long as i see a symmetrical profile, i can stop the iterations without having the software saying'solution converged?

 August 3, 2002, 13:05 Re: Need desperate help in convergence #4 Erwin Guest   Posts: n/a Yes, the convergence criteria are artifical. Use your brain, look at your solution, decide for yourself, don't wait for the software to come up with something intelligent.

 August 4, 2002, 01:22 Re: Need desperate help in convergence #5 Puck Guest   Posts: n/a okie thnx.. will do tht in future.

 August 11, 2002, 21:23 Re: Need desperate help in convergence #6 Alamgir Guest   Posts: n/a 10^(-5)=0.00001, not 0.000001. Erwin is right, u can stop after getting your desire profile don't bother with the residuals or saying "equation is converged". Alamgir

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