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[Sponsors] |
March 29, 2005, 15:53 |
Boundary condition
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#1 |
Guest
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Is it possible to specify both the specified flux and the specified value outlet for the boundary condition of the UDS? I suppose that it is possible with a user-defined function but I don't know how and I can't find the informations in the manuel.
Salutation, David |
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March 29, 2005, 16:00 |
Re: Boundary condition
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#2 |
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You shouldn't do that because it's not matematically meaningful. If you fix the value of a variable, also its flux will be calculated accordingly and viceversa.
Best regards, ap |
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March 30, 2005, 02:49 |
Re: Boundary condition
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#3 |
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Hi david What do you mean by ficing the gradient anf fiixng the value of the variable. Z
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March 30, 2005, 10:33 |
Re: Boundary condition
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#4 |
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You're right. I forgot it.
Salutation, David |
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