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- - **HELP!! Prandtl numbers in RNG k-e turbulence model
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HELP!! Prandtl numbers in RNG k-e turbulence model
According to the RNG theory, the inverse effective Prandtl numbers for K and e is about 1.393 in the high-Reynolds-number limit. That means the Prandtl numbers for k and the Prandtl numbers for k e are the same and equal to 0.7179.
I want to use RNG k-e turbulence model to run my case --the wind flow through the buildings. I know the contants of Cmu, C1e, C2e, Prandtl numbers for k and Prandtl numbers for e for RNG k-e turbulence model. But how can I define the Prandtl numbers for k 0.7179 and Prandtl numbers for e 0.7179 in Fluent when I use RNG k-e turbulence model? |

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