The index of UDS

July 10, 2006, 19:18

Hello, everyone. Now I am working on the user-defined scalar, and the source term concludes this user-defined scalar itself. May I use C_UDSI_MI(c, thread, i) to include the effect of the scalar itself? The document says that i is the index of the scalar. But I still confused with its meaning. Could you please give me some explanation of it, as well? Thanks very much.

July 11, 2006, 06:36

i is used to identify which scalar equation you would like the macro to access. if you are using more than one UDS the equations will be uds-0, uds-1, uds-2 etc. so set i=0 for uds-0 and i=1 for uds-1 and so on

July 10, 2006, 19:18	The index of UDS	#1
chris Guest Posts: n/a	Hello, everyone. Now I am working on the user-defined scalar, and the source term concludes this user-defined scalar itself. May I use C_UDSI_MI(c, thread, i) to include the effect of the scalar itself? The document says that i is the index of the scalar. But I still confused with its meaning. Could you please give me some explanation of it, as well? Thanks very much.

July 11, 2006, 06:36	Re: The index of UDS	#2
cadaei Guest Posts: n/a	i is used to identify which scalar equation you would like the macro to access. if you are using more than one UDS the equations will be uds-0, uds-1, uds-2 etc. so set i=0 for uds-0 and i=1 for uds-1 and so on

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