turbulent kinetic energy in 2D ke model
Dear All,
I have a problem about the turbulent kinetic energy in 2D ke model. I would like to ask when considering 2D cases, the turbulent kinetic energy is ((u')^2+(v')^2)/2 or ((u')^2+(v')^2+(w')^2)/2 ? Thanks, pH 
Re: turbulent kinetic energy in 2D ke model
turbulent kinetic energy is just the trace of the reynolds stress tensor so sould be, ((u')^2+(v')^2)/2

All times are GMT 4. The time now is 03:07. 