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turbulent kinetic energy in 2D k-e model

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Old   January 30, 2007, 23:11
Default turbulent kinetic energy in 2D k-e model
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Dear All,

I have a problem about the turbulent kinetic energy in 2D k-e model.

I would like to ask when considering 2D cases, the turbulent kinetic energy is ((u')^2+(v')^2)/2 or ((u')^2+(v')^2+(w')^2)/2 ?

Thanks, pH
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Old   January 31, 2007, 09:55
Default Re: turbulent kinetic energy in 2D k-e model
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turbulent kinetic energy is just the trace of the reynolds stress tensor so sould be, ((u')^2+(v')^2)/2

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