instantaneous frames of vortex shedding
i am doing a unsteady flow problem across a square cylinder.i got good vortex shedding. No. of time step= 800 time step size= 0.02 Max No. of iteration per time step=30 i got a vortex shedding frequency of 1.5 therefore,time period =1/1.5=0.66 now i want to get 20 instantaneus frames within one cycle time of vortex shedding...how to get that... hoping an early reply..
thanks in advance
Re: instantaneous frames of vortex shedding
I suppose your time step size should be 0.66/20 =0.033 sec.
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