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Force at wall in pipeflow

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Old   June 3, 2009, 06:40
Default Force at wall in pipeflow
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Gunposer
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Hi there,
How does Fluent calculate the force at a wall in 2D. Isn't there a prob with the z-cord., to calculate the Area like
[latex]$F=0.5\rho v^2 A$[/latex]

Greetz Gun
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Old   June 3, 2009, 08:36
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mj sharawi
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Hi
In 2D cases, Fluent calculates the area for a unit width in the z-direction. Whereas in 2D-axi-symmetric, it calculates for one radian rotation.
Hope this answers your question.
MJ
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Old   June 8, 2009, 04:01
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Gunposer
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Thank you for your quick reply,
does it mean, if I've got a wall with units of mm I multiply the

"lenght x 1mm"

to get the area?
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Old   June 8, 2009, 05:21
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Attached I am sending my problem.
IT is 2D laminar Fluid.
The wall in the red frame is called wallleft.
Fluent reports me the wallleft force.

Now I trie to understand, how Fluent calculate.

Density 1400kg/m
Viscosity 2100Pas
v=0.1m/s

height = 0.1mm => A=0.1*10^-3 m * 1*10^-3 m = 10^(-7)m

==> F=7*10^-7 N

But is my calculation right. How do I found out the Force at the wall. I dont understand the force report of Fluent, attached to the picture. Hope, somebody can give me support.

Greez Gunnar
Attached Images
File Type: jpg wallleft.jpg (51.6 KB, 8 views)
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