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October 6, 2009, 04:18 |
Courant number for steady state modeling
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#1 |
New Member
Sean
Join Date: Mar 2009
Posts: 15
Rep Power: 17 |
Hi,
As I know courant number has a correlation with time step(C=v×Δt/ΔL). But for steady state modeling, there is no time step setting at all. So, here is my question. Q: How to understand courant number in steady state modeling? Thank you! |
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October 6, 2009, 04:33 |
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#2 |
Senior Member
Svetlin Filipov
Join Date: Mar 2009
Location: United Kingdom
Posts: 176
Rep Power: 17 |
It depends of what you understand under steady state calculation... for some tasks it is not possible to obtain time independent solution (may be you knowledge about steady state ) so you have a small enough time period in which the solution is transient, but this "picture" is repeated many times in time....
I hope you understand.. |
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October 6, 2009, 05:00 |
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#3 |
New Member
Sean
Join Date: Mar 2009
Posts: 15
Rep Power: 17 |
Philipov,
Thank you so much for your reply. I roughly understand. Could you please help me to understand this example? Example: Steady state in density based solver When we use based solver under steady state, we need to always set Courant number. How to understand this courant number? Thank you so much! |
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October 6, 2009, 10:03 |
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#4 |
Senior Member
Svetlin Filipov
Join Date: Mar 2009
Location: United Kingdom
Posts: 176
Rep Power: 17 |
Do not know from where this statement comes from. May be from the Fluent help files?
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