Setting an external B0_x field in MHD module
I'm trying to do a simple simulation of pipe flow flowing through a transverse applied external magnetic field.
I've followed religiously the Manual provided by Ansys but I think it's not doing the job I'm wanting it to do.
In the Problem Set-Up/MHD Model/ I have a DC Field with B0_x Mean (Tesla) as 10 Tesla. I have applied the external field. In the boundary conditions I have a conducting wall.
In the Boundary Conditions section, I have a "Velocity-Inlet", "Pressure-Outlet", "Symmetry", and "Wall". There are UDS tabs for the inlet, outlet and wall zones. I have these all set to udf mhd_bc_conduct::mhd.
I'm not too sure what these UDS BV actually do... so if someone would want to elucidate?
I then initialize the problem etc. and the solution turns up exactly like there was no external applied magnetic field! During solving iterations, it also prints out residuals for uds-0, uds-1, uds-2.. and these are all zero, so I'm guessing it's not considering the huge magnetic field that I'm applying?!
For the record, in the Results section, when I display the Contour for Symmetry of "User Define Memory" / B0_x I get a pretty homogeneous 10 Tesla!
I know for a fact that the liquid (fast flowing molten metal) changes it's behaviour but it appears like it's not considering the applied external magnetic field?!
Fortunately I figured this out myself.
The reason is that you have to click "Apply" for the external magnetic field in the problem set-up AFTER initializing the solution... i believe that by initializing the solution in general it cancels the application of the external magnetic field done by the MHD module. The MHD manual is a bit counter-intuitive in this regard!
Hello Mr Fferroni,
I was wondering if you could help me out with this problem related to MHD using Fluent.
I have been trying to implement conducting wall boundary condition for the MHD module using the Electric Potential Method. It requires to specify a fixed current or voltage.
I am trying to simulate turbulent flow in a square pipe and have not been able to figure out a way to calculate the required potential/voltage at the boundary.
Please comment if you have any ideas.
Thanks in advance.
hi mr. fferroni,
i was facing the same the same the problem .But your suggestion worked. thanks a lot.
but i am not able to get the lorentz force contour and also i am not sure bout boundary condition for uds-0 and uds-1. If you have any idea then please tell me .
the total magnetic flux through a closed surface is equal to zero. if your surface is close you havnt any induce magnetic field b.
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