|October 8, 2012, 05:49||
kinetic energy of rotating fluid flow
Join Date: Oct 2012
Posts: 1Rep Power: 0
For a rotating rigid body which is translating at the same time, the total kinetic energy= translation energy (1/2*mass*velocity^2)+rotational energy (1/2*moment of inertia*vorticity^2).
However, would like to ask - for fluid flow which is rotating (such as vortex) and translating simultaneously, does the total kinetic energy=translation energy (1/2*density*velocity^2)+rotational energy (1/2*radius*vorticity^2)??
|October 8, 2012, 06:20||
Join Date: Dec 2011
Location: Madrid, Spain
Posts: 133Rep Power: 6
Hi Abbie. No, the kinetic energy of the fluid particles is entirely accounted for in the first term of your equation (1/2*density*velocity^2), because the velocity vector includes the longitudinal and the tangential component. Otherwise you would be accounting for the rotation of the fluid to the kinetic energy twice.
Last edited by michujo; October 8, 2012 at 08:50.
|kinetic energy; flow|
|Thread||Thread Starter||Forum||Replies||Last Post|
|How to view subgrid kinetic energy||Craig||FLUENT||3||September 8, 2012 11:34|
|Computation of kinetic energy of the flow||feldy77||OpenFOAM||3||November 10, 2011 16:43|
|Flow meter Design||CD adapco Group Marketing||CD-adapco||3||June 21, 2011 08:33|
|question about turbulent kinetic energy||junker4236||Main CFD Forum||8||December 24, 2010 04:06|
|some fluid dynamics terms||Usman||Main CFD Forum||4||January 19, 2008 22:00|