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kinetic energy of rotating fluid flow

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Old   October 8, 2012, 05:49
Default kinetic energy of rotating fluid flow
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Abbie Chan
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Dear all,

For a rotating rigid body which is translating at the same time, the total kinetic energy= translation energy (1/2*mass*velocity^2)+rotational energy (1/2*moment of inertia*vorticity^2).

However, would like to ask - for fluid flow which is rotating (such as vortex) and translating simultaneously, does the total kinetic energy=translation energy (1/2*density*velocity^2)+rotational energy (1/2*radius*vorticity^2)??

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Old   October 8, 2012, 06:20
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Hi Abbie. No, the kinetic energy of the fluid particles is entirely accounted for in the first term of your equation (1/2*density*velocity^2), because the velocity vector includes the longitudinal and the tangential component. Otherwise you would be accounting for the rotation of the fluid to the kinetic energy twice.


Last edited by michujo; October 8, 2012 at 08:50.
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