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 October 20, 1999, 21:23 Please help a high school student! Please #1 JEK Guest   Posts: n/a Help! How much pressure must a submarine withstand at a depth of 120.0 m? The answer according to my teacher is 1205 kPa, I don't believe her. Your thoughts?

 October 20, 1999, 23:15 Re: Please help a high school student! Please #2 clifford bradford Guest   Posts: n/a let's see.hydrostatic pressure is given by: P=rho*g*h so P=1000*10*120 P=1200kPa seems she's right. the numbers are approximate since the density of seawater is over 1000kg/m^3 and g=9.81 but the ballpark is good. believe your teacher.she has a degree.

 October 20, 1999, 23:16 Re: Please help a high school student! Please #3 Glenn Horrocks Guest   Posts: n/a Hi, Your teacher is about right. pressure = density * g * depth Where: density = 1000 kg/m^3 (It's a bit higher for salt water but this will do) g = 9.8 m/s^2 depth = 120 metres So the pressure will be 1.2 MPa. Cheers, Glenn

 October 21, 1999, 11:22 Re: Please help a high school student! Please #4 Md. Ziaul Islam Guest   Posts: n/a Dear JFK, Let me try to explain to you in a very simple way. In this condition, the pressure of a submarine depends upon density, g, and depth. Density of salt water may vary a little bit from place to place in the ocean depending upon the amount of salt dissolved in water. Value of g varies slightly depending upon the distance of the submarine from the center of the earth. In this situation, assuming the value of g and density of salt water constant is a clever approach. So what we have now is the depth of the submarine from the surface of water. Deeper is the location of the submarine from the water surface, higher is the pressure on the submarine and vice versa. Now you can realize that the pressure on the submarine is proportional to the depth keeping the other two parameters (g and density) constant.

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