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Shuo September 2, 2008 21:39

mixed difference
 
A second-order centreal mixed difference scheme is given as

du/dxdy|i,j = (u_i+1,j+1 + u_i-1,j-1 - u_i-1,j+1 - u_i+1,j-1)/ (4*delta_x*delta_y)

How can I treat the boundary points? (i.e. du/dxdy|0,0)

Thanks Shuo

EagleGao September 3, 2008 01:25

Re: mixed difference
 
Biased difference scheme, forward or backward stencils


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