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cfdguy November 1, 2008 20:18

CFD guy
I have solved the isotropic turbulence decay in 3D but the decay does not look like the one that I saw in 2D.

Can some one explain?

Thanks in advance

Amod November 7, 2008 08:54

Re: CFD guy
It may be because Turbulence is inherently a 3D phenomena. Hence 3D simulation would be more realistic as compared to 2D one.


Tom November 7, 2008 10:44

Re: CFD guy
You need to read up on this - try, for example,

"The Theory of Homogeneous Turbulence" by G.K. Batchelor


"Turbulence: An Introduction for Scientists and Engineers" by P.A. Davidson.

Basically the energy and enstrophy cascades are different in 2D and 3D.

The main reason why 2D and 3D flows are different is, and is actually why it's fair to say that there is no such thing as 2D turbulence in the strictest sense, the absence of the vortex stretching term in the 2D vorticity equation.

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