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NS eq: 3D unsteady compressible to axisymmetric cylindrical 2D laminar+incompressible

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Old   November 17, 2015, 03:44
Default NS eq: 3D unsteady compressible to axisymmetric cylindrical 2D laminar+incompressible
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I've been wracking my brain over this question, can anyone shed some light:

Convert 3 dimensional unsteady compressible NS equations to axisymmetric 2 dimensional incompressible laminar form for a cylindrical pipe.ignore gravity

I figured I need to use the cylinderical form of NS equations, which is r, theta and z component. But then I'm lost...
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Old   November 17, 2015, 04:03
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Filippo Maria Denaro
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if I am right, a typical set of equations is described in:

J. Fluid Mech., 179, 179-299, 1987
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Old   November 17, 2015, 04:15
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Originally Posted by FMDenaro View Post
if I am right, a typical set of equations is described in:

J. Fluid Mech., 179, 179-299, 1987
Thanks FMDenaro,

I can't seem to access the journal, can you suggest another source?
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Old   November 17, 2015, 04:39
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many good textbook illustrate the set of equations you want ...
Maybe, you can find them aslo in the wiki page
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Old   November 17, 2015, 04:41
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you can start from here http://ingforum.haninge.kth.se/armin..._STOKES_EQ.pdf

and setting the symmetry constraint
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Old   November 18, 2015, 22:40
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Quote:
Originally Posted by rere View Post
I've been wracking my brain over this question, can anyone shed some light:

Convert 3 dimensional unsteady compressible NS equations to axisymmetric 2 dimensional incompressible laminar form for a cylindrical pipe.ignore gravity

I figured I need to use the cylinderical form of NS equations, which is r, theta and z component. But then I'm lost...
Since you are to start from unsteady compressible NS equations, you need to do more than just coordinate transformation and reduction. Start with the compressible equation set in cylindrical coordinates. Then you need to zero out all of the transient terms, take the limit as the density goes to a constant and div U goes to zero. Axisymmetry implies that all theta derivative terms go to zero as well. And eliminate the body force term.

The mass equation will collapse to div U = 0. The energy equation will decouple because there is no density dependence on temperature. The momentum equation will lose the second coefficient of viscosity term because div U = 0. Note that U in the theta direction may be non-zero (swirl velocity), so only d/dtheta terms vanish, not all U_theta terms.
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Old   November 19, 2015, 07:15
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YEs, I agree ... It is also quite common to start from the set of equations in general vectorial expression, setting all hypotheses (constant density, constant temperature, steady flow, etc.) and derive the vector form of the incompressible equation.

Then the vectors and nabla operators can be expressed in the reference system you want to use
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Old   November 28, 2015, 04:53
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Quote:
Originally Posted by mprinkey View Post
Since you are to start from unsteady compressible NS equations, you need to do more than just coordinate transformation and reduction. Start with the compressible equation set in cylindrical coordinates. Then you need to zero out all of the transient terms, take the limit as the density goes to a constant and div U goes to zero. Axisymmetry implies that all theta derivative terms go to zero as well. And eliminate the body force term.

The mass equation will collapse to div U = 0. The energy equation will decouple because there is no density dependence on temperature. The momentum equation will lose the second coefficient of viscosity term because div U = 0. Note that U in the theta direction may be non-zero (swirl velocity), so only d/dtheta terms vanish, not all U_theta terms.
mprinkey, this is the question i mentioned in the PM. Thank you.

Last edited by rere; November 28, 2015 at 08:10.
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