Momentum Source Term in SIMPLER Algorithm

ravachol · June 12, 2016, 11:46

Hello all,

I am trying to write a code based on SIMPLER algorithm of Patankar by following the book of Versteeg. There is no source term for my study, I am imposing the exact values of the boundary points on a staggered grid. Do i still need to define any value to the b (momentum source term) in the momentum equation or it is just needed for implementing boundary conditions?

$a_{e}U_{e}=\sum_{nb}a_{nb}U_{nb}+b+\left(p_{P}-p_{E}\right)A_{e}$

Any idea will be greatly appreciated,

Thanks in advance

arjun · June 12, 2016, 14:10

If there is no force for example say gravity etc, then b is 0.

Quote:

Originally Posted by ravachol

Hello all,

I am trying to write a code based on SIMPLER algorithm of Patankar by following the book of Versteeg. There is no source term for my study, I am imposing the exact values of the boundary points on a staggered grid. Do i still need to define any value to the b (momentum source term) in the momentum equation or it is just needed for implementing boundary conditions?

$a_{e}U_{e}=\sum_{nb}a_{nb}U_{nb}+b+\left(p_{P}-p_{E}\right)A_{e}$

Any idea will be greatly appreciated,

Thanks in advance

erkan · June 15, 2016, 07:17

Thank you very much Arjun,

I am using air as working fluid, so I will neglect the weight of the fluid. Then the two dimensional momentum equation for this case would be:

$a_{p}U_{p}=a_{w}U_{w}+a_{e}U_{e}+a_{n}U_{n}+a_{s}U_{s}+\left(p_{P}-p_{E}\right)A_{e}$

June 12, 2016, 11:46	Momentum Source Term in SIMPLER Algorithm	#1
ravachol New Member Join Date: Jun 2016 Posts: 2 Rep Power: 0	Hello all, I am trying to write a code based on SIMPLER algorithm of Patankar by following the book of Versteeg. There is no source term for my study, I am imposing the exact values of the boundary points on a staggered grid. Do i still need to define any value to the b (momentum source term) in the momentum equation or it is just needed for implementing boundary conditions? $a_{e}U_{e}=\sum_{nb}a_{nb}U_{nb}+b+\left(p_{P}-p_{E}\right)A_{e}$ Any idea will be greatly appreciated, Thanks in advance

June 15, 2016, 07:17		#3
erkan New Member Join Date: Mar 2009 Location: Turkey Posts: 15 Rep Power: 17	Thank you very much Arjun, I am using air as working fluid, so I will neglect the weight of the fluid. Then the two dimensional momentum equation for this case would be: $a_{p}U_{p}=a_{w}U_{w}+a_{e}U_{e}+a_{n}U_{n}+a_{s}U_{s}+\left(p_{P}-p_{E}\right)A_{e}$ __________________ Timeo hominem unius libri

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