rotational and inviscid

 Register Blogs Members List Search Today's Posts Mark Forums Read

 July 7, 2000, 13:46 rotational and inviscid #1 Mike Guest   Posts: n/a Does anyone please tell me if inviscid flow can be rotational or not? What is the nature of rotational flow?

 July 7, 2000, 14:09 Re: rotational and inviscid #2 Adrin Gharakhani Guest   Posts: n/a Yes. Inviscid flow can be rotational. Rotational flow may be characterized by vorticity, which is the curl of velocity. A simple example is a vortex ring (like a cigarette smoke puff but without the diffusion process) Check out fundamental fluid dynamic books. It is important NOT to confuse potential flow with inviscid flow (which may be the source of your confusion). While potential flow satisfies the equation of motion of inviscid flow dynamics, the reverse is not necessarily true. That is, an inviscid flow is not necessarily potential (the former may contain vorticity, which induces rotational and not potential flow) Adrin Gharakhani

 July 7, 2000, 15:16 Re: rotational and inviscid #3 Kalyan Guest   Posts: n/a Inviscid flow can be rotational. As pointed out in an earlier reply, inviscid flows with vortices are good examples. It might help to know that vorticity is conserved in inviscid flows, i.e., Euler equations are incapable of vorticity production. So in an inviscid flow computation, vorticity (in the form of point vortices or vortex blobs or continuous fields) can only come in as a part of the inflow and can not be produced or destroyed by the Euler equations. Note also that the vortex rings can never be formed without viscosity though they can exist in a purely inviscid fluid.

 July 7, 2000, 15:26 Re: rotational and inviscid #4 Adrin Gharakhani Guest   Posts: n/a > Euler equations are incapable of vorticity production. So in an inviscid flow computation, vorticity (in the form of point vortices or vortex blobs or continuous fields) can only come in as a part of the inflow and can not be produced or destroyed by the Euler equations. This is true _only_ for the incompressible (and constant density) case. Example: baroclinic vorticity generation (without solid boundaries). Adrin Gharakhani

 July 7, 2000, 20:33 Re: rotational and inviscid #5 John C. Chien Guest   Posts: n/a (1). It is not a good idea to mix these two terms at the same time. (2). At the begining, you have this equation called the Navier-Stokes equations, which represent the conservation of mass, momentum and energy. It contains viscosity terms. (3). Now, if you take the curl operation on the momentum equations, you will get this so-called "vorticity" equation. Remember that, the vorticity equation is derived from the momentum equation, so it has viscosity terms in it also. (4). If you set the viscosity terms to zero, you are going to get this mathematical equation, called "inviscid" equations, whether it is the inviscid momentum equations or the inviscid vorticity equation. (5). The inviscid momentum equation is generally called "Euler Equation" in contrast to the Navier-Stokes equations which has viscosity terms. (6). In the vorticity equation(derived from the Navier-Stokes equations), in addition to the viscosity terms, there are convection terms, stretching terms, production terms due to expansion, non-uniform density, and general body force. (7). So, even though you drop the viscosity terms, there are still many other terms in the vorticity equation, including the production terms. (8). So far, we have touched only the "inviscid" vs "viscous" forms of equation. (9). The rest of that is easy. The only time when the flow is "irrotational" is when the vorticity is everywhere zero. If there are still many terms in the vorticity equation (after dropping the viscosity terms), then you know that vorticity is normally non-zero. So, most of the time, it is rotational even without viscosity terms. (10). In old days, the inviscid equation was still very difficult to solve. So, the Euler equation was further simplified (second time) by setting the vorticity to zero (it is called "irrotational"). As a result, one can express the velocity in terms of the velocity potential and derive the so-called "potential flow"equation. (11). So, "potential flow" is "irrotational flow". And for the incompressible flow, the equation is the Laplace equation. The Laplace equation was the main focus in the 19th century. (12). Remember that, Euler equation and Laplace equation are simplified equations derived from the Navier-Stokes equations.(by setting the viscosity to zero, and then by setting the vorticity to zero, respectively)

 July 14, 2000, 15:31 Re: rotational and inviscid #6 clifford bradford Guest   Posts: n/a curved shocks can be a source of vorticity in an inviscid flow. i think there may be other potential sources but I can't remember what the others might be.

 July 20, 2000, 12:39 Re: rotational and inviscid #7 Hua Zhou Guest   Posts: n/a where the velocity varies, where there exist vortex; where the entropy increases, where creates vortex.

 April 20, 2011, 02:25 #8 Senior Member   Nick Join Date: Nov 2010 Posts: 120 Rep Power: 6 Many thanks guys you explained things that confused me for awhile. Especial thanks to Adrian, John and Kalyan

 Thread Tools Display Modes Linear Mode

 Posting Rules You may not post new threads You may not post replies You may not post attachments You may not edit your posts BB code is On Smilies are On [IMG] code is On HTML code is OffTrackbacks are On Pingbacks are On Refbacks are On Forum Rules

 Similar Threads Thread Thread Starter Forum Replies Last Post pablodecastillo OpenFOAM Running, Solving & CFD 7 June 16, 2012 08:15 Rjakk Main CFD Forum 2 March 21, 2007 11:53 Atit Koonsrisuk CFX 12 January 2, 2003 13:40 Jitendra Main CFD Forum 9 July 5, 2000 14:58

All times are GMT -4. The time now is 00:54.