|March 9, 2010, 04:54||
number of swirl formula
Join Date: Mar 2010
Posts: 1Rep Power: 0
I have a problem concerning the number of swirl.I know that swirl number is equal to the ratio between the axial flux of angular momentum and the flux of axial momentum
S = Gtheta / (R * Gz) with R radius of duct
I suppose that:
angular coordinate : Er, Etheta, and Ez
U -> axial velocity. V -> circunferencial velocity. r -> radial coordinate. theta -> angular coordinate R -> the pipe radius.
I don't understand the formula. where does the axial veloxity term come from in the angular momentum and axial momentum
for me angular momentum is equal (in angular coordinate) to (r.Er)^(density.v.Etheta) =r.v.density.Ez and the flux is equal to the surface integral between 0 to R and 0 to 2Pi of (density.r.v.Ez).(r.dr.dtheta.Ez) = density.rē.v.dr.dtheta.
In the doc, we find density.rē.v.u.dr.dtheta. idem for axial momentum
see the link below
Thanks for your help
|March 9, 2010, 15:02||
Join Date: Jul 2009
Posts: 232Rep Power: 11
If the axial momentum is rho*U, and the axial velocity component is the component normal to the constant Z face, then wouldn't the axial flux of axial momentum simply be rho*U*U?
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