# Boundary Conditions Pressure Poisson Equation

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 October 12, 2004, 05:06 Boundary Conditions Pressure Poisson Equation #1 Oscar Salazar Guest   Posts: n/a Hi I am simulating the flow in a pipe using incompressible cylindrical 2D Navier-Stokes velocity-pressure formulation. I am applying the projection method to solve Poisson pressure equation (Chorin 1968): [1/r]dP/dr + d²P/dr² + d²P/dz² = f(Uz*,Ur*) the following boundary conditions are right? Inflow (z=0): Uz(0,r) = 3 , Ur(0,r) = 0 , dP/dz = 0 Outflow (z=L): dUz/dz = 0 , Ur(0,r) = 0 , P(L,r)= 0 Center (r=0): dUz/dr = 0 , Ur(z,0) = 0 , dP/dr = 0 Wall (r=R): Uz(z,R) = 0 , Ur (z,R) = 0 , dP/dr = 0

 October 12, 2004, 11:37 Re: Boundary Conditions Pressure Poisson Equation #2 Junseok Kim Guest   Posts: n/a Inflow (z=0): Uz(0,r) = 3 , Ur(0,r) = 0 , dP/dz = 0 Outflow (z=L): dUz/dz = 0 , Ur(0,r) = 0 , P(L,r)= 0 You may want to use following, Inflow (z=0): Uz(0,r) = 3(R+r)(R-r)/R^2 , Ur(0,r) = 0 , dP/dr = 0 because Ur(0,r) = 0 Outflow (z=L): d^2Uz/dz^2 = d^2Ur/dz^2 =d^2P/dz^2 = 0

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