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December 9, 2010, 19:54 
Solving ke model

#1 
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Alexander Ruth
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Hi, I am writing a code with FORTRAN to solve the ke model. I have a Problem with the eddy viscosity formulation. The flow I like to predict is one over a rotating disc. This flow is considered to disappear in the infinty and so at the end of the grid (far away from the disc) too.
So k and e become zero far away from the disc....my problem is that in formulation of the eddy viscosity for the ke model i have to calculate kČ/e....and this causes problems because k is in the infinity 1+10^30 and e is 1*10^33....so kČ/e is becoming something like 1000 but it should be zero. Has anybody an idea how I can solve this? Thanks! Alex 

December 10, 2010, 03:19 

#2  
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Alexey
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December 15, 2010, 09:59 

#3 
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jk
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Dear Mr Ignat,
I have developed a 2d collocated pipe flow cfd code. I am trying to implement turbulence model into it (simple prandtl's mixing length model). But after implementation turbulence profile looks more peaky than the laminar profile at the exit. Can you suggest me some solution for this error. Thanks in advance 

December 15, 2010, 15:35 

#4  
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Alexey
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As I know prandtl's mixing length model is too rough. I recommend you to use SpalartAllmaras model without ft2 term. Look here http://turbmodels.larc.nasa.gov/spalart.html It is simple oneequation model for one variable with noproblem boundary conditions. For pipe flows it gives good resuts. Be careful with boundary conditions for velocity at the wall. If closest cell size > then 10 (in wall units y+) you should use wallfunction  logarithmic profile. 

December 16, 2010, 06:40 

#5 
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jk
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Dear Mr ignat,
Thankyou for your message. One more doubt is that you said to be cautious at the wall boundary condition for velocity, confused whether to give the wall velocity zero or not. Actually from the log law layer expression are we finding the tou_w (wall shear stress) ? Can you please clear this doubt. Thanks 

December 18, 2010, 13:59 

#6  
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Alexey
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Sorry for delay so forum was down ! (many thanks to cfdonline team for fast restoring) In fact, that noslip condition on the wall does not contradict with condition =(any value). You can use either of them. Since wall shear stress is the momentum flux it can be viewed as boundary condition (BC) for momentum equation written in conservation form. If closest mesh node is placed inside laminar sublayer (which veryvery thin) then better choice is . But if closest node is far from the wall (y+>10) then better choice for BC is 

December 22, 2010, 07:30 

#7 
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jk
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Dear Mr Ignat
Extremely thankful for your reply. Can you please check the following procedure that i am going to implement in my laminar code Procedure pertaining to turbulence  1 Assume tou_w (wall shear stress) to some initial value 2 Then find y+ according to the formula y+ = row * ut * y/meu 3 Substitute this y+ value in the tou_w expression obtained from loglaw layer Then add this tou_w to the momentum equation as a source term along with the dp/dx like this (neglecting ‘a s’ term) apUp=awUw+anUn+aeUe+(dp/dx) * volume + (tou_w x area) but for v momentum equation apVp=awVw+anVn+aeVe+asVs +(dp/dy)*volume Overall procedure as follows


December 22, 2010, 10:08 

#8  
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Alexey
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Is this algorithm your own invention? Sorry,but I think it does't work. Don't think up your own methods. Time is money. The better way is to study well known and robust methods for calculation of incompressible flows. I recommend you to use some staggered grid algorithm, for example this Kim, J., Moin, P., Application of FractionalStep Method to Incompressible NavierStokes Equations. // J.Comp.Phys. 1985, v.59, pp. 308323 or some others which use staggered grid, but not collocated one because for collocated grids there is a problem of pressurevelocity link. Some about boundary condition. I do the following way. In order to calculate you should solve the equation: and find where is known velocity at closest node, is the distance from the closest node to the wall and is the molecular kinematic viscosity. This is transcendental equation and it is simply solved by Newton iterations with initial guess for small value, for example 0.00001 Then . (1) On the other hand (2) where is the false velocity at the false node outside the domain which is placed at the same distance . From (1) and (2) you find and use it as boundary condition for momentum equation. Look picture Last edited by ignat; December 22, 2010 at 15:20. 

December 22, 2010, 15:17 

#9  
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Alexey
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Your variant is correct for OUTFLOW boundary only. 

December 23, 2010, 05:45 

#10 
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jk
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Hi,
Thanks. I think you have mistaken me. It was just a outline only. Actually i have taken care of all those pressurevelocity coupling problems. Infact i had a systematic start in coding with 1d staggered solver then 2d staggered, 1d colocated and then 2d colocated. Now for this 2d colocated code i am trying to implement the turbulence model. (Basically mine is an incompressible flow solver). I will use your ideas to implement the boundary condition for the turbulence. thankyou jyothishkumar 

December 23, 2010, 10:33 

#11 
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Alexey
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Hi jyothishkumar
It was really misunderstanding, sorry. That's ok. Best regards, 

December 29, 2010, 02:14 

#12 
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Amir
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Hi
Use Teach code as a pattern. Amir 

December 29, 2010, 04:38 

#13 
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jk
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hi amir,
what is this Teach code. Is it something to tell about turbulence model implementation ? thanks jyothish 

March 31, 2011, 03:14 

#14 
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jk
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Dear Mr Ignat,
I am trying with k epsilon turbulence implementation in my code (std k epsilon). I am just following the malalasekara book (latest edition) for this implementation. Or please tell me the ideas like what is the source term to be added in momentum eqn etc etc. how to handle the source term in k epsilon equation. Whether to solve for k equation for the first node or can i use directly like k = utou^2/sqrt(cmu). Thanks in advance jyothish 

March 31, 2011, 07:20 

#15  
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Alexey
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As I know standard ke model is very stiff so both of equations have to be solved implicitly. Both kequation source term and eequation one must be linearized and approximated at n+1 time level. Moreover, diffusion terms in both equations have to be solved implicitly too. This way usually can avoid negative k & e values. wish good luck. 

August 10, 2012, 06:09 
Prandtl mixing length implementation

#16 
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Michael Moor
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Hi everyone,
I have succesfully created a solver in Matlab for 2d STEADY incompressible Poiseulle flow, using a backward staggered grid, FVM, SIMPLE algorithm and hybrid differencing scheme, with good results to HagenPoiseulle velocity profile. Boundary conditions are inletoutlet, with the walls being brought into the domain the wall shear stress, (I have stuck rigidly to Versteeg). I am now at the stage of adding turbulence models. I understand from Patankar, that it is best to leave out the Reynolds stress terms in the momentum equations explicitly, but to the use the effective viscosity, which is the dynamic + turbulent. (mu_eff =mu + mu_t). Turbulence modelling: In the RANS and 2D flow, the only relevant reynold stress is tau_xy, which we then discretise d(tau_xy)/dy for a cell volume, i.e. (tau_xy*A)n  (tau_xy*A)s, where n & s are the north and south FACES, and tau_xy, for the Prandtl mixing length is: rho*mixing_length^2*du/dy^2. Again, du/dy is ((u)n  (u)s)/deltayp. Similarly for the vmomentum, except now (tau_xy*A)e  (tau_xy*A)w.... du/dy is still the same. I feel ashamed having to ask about discretisation! lol! I just want to be sure and do not have time for second guessing myself!! mixing length for pipe flow is L[0.140.08(1y/L)^2  0.06(1y/L)^4], where y is the distance from the node to the wall , L is the radius/ half channel width. Therefore, for each u and v cell, i must calculate: 1. the mixing length, with y being the distance from the wall to the ucell centre 2. the velocity gradient ((u)n  (u)s)/deltayp, where the value of (u)n or (u)s will be linearly approximated by, e.g. (u)n = (u(i,J) + u(i,J+1))/2 3. 1 & 2 allows me to calculate tau_xy 4. now, to get the value of tau_xy at cell faces, use central differencing? 5. along wall nodes, do i use u+ instead of up to calculate the shear stress and add it in the source serm b? It is SUPPOSED to be quick and easy to implement... so I appreciate any assistance. following this, i want to add kepsilon Best regards, Michael 0565113@gmail.com 

August 10, 2012, 13:18 

#17  
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Michael Moor
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