CFD Online Logo CFD Online URL
www.cfd-online.com
[Sponsors]
Home > Forums > General Forums > Main CFD Forum

Transient Simulations - Effect of number of grid points

Register Blogs Community New Posts Updated Threads Search

Reply
 
LinkBack Thread Tools Search this Thread Display Modes
Old   April 16, 2018, 06:03
Smile Transient Simulations - Effect of number of grid points
  #1
Member
 
thedal's Avatar
 
Thamilmani M
Join Date: Sep 2017
Location: IIT Bombay, Mumbai
Posts: 52
Rep Power: 8
thedal is on a distinguished road
Hello everyone,

I am working on a transient 2D laminar flow over two tandem cylinders in ANSYS. I used finer mesh by using different grid points on each side of cylinder. Let that be a. I used values of 40, 60 and 80. so that the total number of cells also keep increasing as we increase a.

Now, I got the a 80 converges to a steady solution after around 5 lakh iterations. But a 40 or a 60 has run even more than that many iterations, but didn't converge to a steady solution, but the Cl plots are just growing.

We know that, increasing number of grid points increase the fineness of the mesh, which improves the accuracy of the solution, however also increase the computational time greatly. But, Here we see that decreasing the number of grid points didn't actualy reduce the computational time as expected. Though a 80 would still be at higher accuracy. Why?

Following case conditions are same of all those meshes:

Upstream distance is 10D, and Downstream distance is 20D and the walls are at 10D each. Re is 100. With PISO solver. All discretizations are Second order.

Can anyone reason out this Why? Or is there something fundamentally wrong in me?

Thanks for all.

Always
Thedal...
__________________
Always
Thedal
thedal is offline   Reply With Quote

Old   April 16, 2018, 07:00
Default
  #2
Senior Member
 
Filippo Maria Denaro
Join Date: Jul 2010
Posts: 6,768
Rep Power: 71
FMDenaro has a spectacular aura aboutFMDenaro has a spectacular aura aboutFMDenaro has a spectacular aura about
What is wrong is that at Re=100 the solution is physically unsteady. Are you using second order upwind?
I can suggest to try the NITA setting the second order central discretization. Then, be careful about the grid resolution around the cylinders
FMDenaro is offline   Reply With Quote

Old   April 16, 2018, 07:23
Default
  #3
Member
 
thedal's Avatar
 
Thamilmani M
Join Date: Sep 2017
Location: IIT Bombay, Mumbai
Posts: 52
Rep Power: 8
thedal is on a distinguished road
Quote:
Originally Posted by FMDenaro View Post
What is wrong is that at Re=100 the solution is physically unsteady. Are you using second order upwind?
I can suggest to try the NITA setting the second order central discretization. Then, be careful about the grid resolution around the cylinders
Dear Sir,

Thanks for the reply. I am using Second Order Implicit scheme for Transient formulations sir. Yes, sir Solution is physically unsteady, But why does a lesser number of cells take more time to converge than a higher one is my primary doubt?
__________________
Always
Thedal
thedal is offline   Reply With Quote

Old   April 16, 2018, 08:06
Default
  #4
Senior Member
 
Filippo Maria Denaro
Join Date: Jul 2010
Posts: 6,768
Rep Power: 71
FMDenaro has a spectacular aura aboutFMDenaro has a spectacular aura aboutFMDenaro has a spectacular aura about
Quote:
Originally Posted by thedal View Post
Dear Sir,

Thanks for the reply. I am using Second Order Implicit scheme for Transient formulations sir. Yes, sir Solution is physically unsteady, But why does a lesser number of cells take more time to converge than a higher one is my primary doubt?

As the case is unsteady, I assume that for "convergence" you do not mean the steady state but the convergence of the iterative methods at each time step. The slower convergence can be due to high local truncation error on the coarse grid as well as to the guess solution that is far from the finaln one.
FMDenaro is offline   Reply With Quote

Old   April 16, 2018, 08:54
Default
  #5
Member
 
thedal's Avatar
 
Thamilmani M
Join Date: Sep 2017
Location: IIT Bombay, Mumbai
Posts: 52
Rep Power: 8
thedal is on a distinguished road
Quote:
Originally Posted by FMDenaro View Post
As the case is unsteady, I assume that for "convergence" you do not mean the steady state but the convergence of the iterative methods at each time step. The slower convergence can be due to high local truncation error on the coarse grid as well as to the guess solution that is far from the finaln one.
Sorry for my misconception and hence the wrong answer, I am actually not asking of the convergence then. Within each timestep, However the convergence is faster than 80, But, to attain steady state, 40 takes more number of timesteps than 80. Why would that be? And Hence more computational time for 40 as well.
__________________
Always
Thedal
thedal is offline   Reply With Quote

Old   April 17, 2018, 07:33
Default
  #6
Member
 
thedal's Avatar
 
Thamilmani M
Join Date: Sep 2017
Location: IIT Bombay, Mumbai
Posts: 52
Rep Power: 8
thedal is on a distinguished road
Quote:
Originally Posted by FMDenaro View Post
As the case is unsteady, I assume that for "convergence" you do not mean the steady state but the convergence of the iterative methods at each time step. The slower convergence can be due to high local truncation error on the coarse grid as well as to the guess solution that is far from the finaln one.
So, There is no relation between the No. of timesteps taken for the flow to attain steady (oscillations are steady) and refinement of mesh?
__________________
Always
Thedal
thedal is offline   Reply With Quote

Old   April 17, 2018, 07:36
Default
  #7
Senior Member
 
Filippo Maria Denaro
Join Date: Jul 2010
Posts: 6,768
Rep Power: 71
FMDenaro has a spectacular aura aboutFMDenaro has a spectacular aura aboutFMDenaro has a spectacular aura about
Quote:
Originally Posted by thedal View Post
So, There is no relation between the No. of timesteps taken for the flow to attain steady (oscillations are steady) and refinement of mesh?

The number of time steps, or better the final time to reach a developed flow, generally depends on the initial condition and on the Reynolds number.

The time step is a parameter depending on the mesh size when the numerical stability constraint must be fulfilled.
FMDenaro is offline   Reply With Quote

Reply

Tags
ansys, computational time, cylinders, meshing, unsteady


Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Trackbacks are Off
Pingbacks are On
Refbacks are On


Similar Threads
Thread Thread Starter Forum Replies Last Post
[snappyHexMesh] Help with Snappy: no layers growing GianF OpenFOAM Meshing & Mesh Conversion 2 September 23, 2020 08:26
Inconsistencies in reading .dat file during run time in new injection model Scram_1 OpenFOAM 0 March 23, 2018 22:29
[OpenFOAM.org] OF2.3.1 + OS13.2 - Trying to use the dummy Pstream library aylalisa OpenFOAM Installation 23 June 15, 2015 14:49
SigFpe when running ANY application in parallel Pj. OpenFOAM Running, Solving & CFD 3 April 23, 2015 14:53
Grid Independent Solution Chuck Leakeas Main CFD Forum 2 May 26, 2000 11:18


All times are GMT -4. The time now is 05:25.