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#21 |
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New Member
Felipe
Join Date: Apr 2010
Posts: 13
Rep Power: 5 ![]() |
how do your results compare to measurements? are you under or over predicting?
In my case I over predict from 10 to 20 degrees |
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#22 |
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New Member
Join Date: Jun 2012
Posts: 25
Rep Power: 2 ![]() |
hi all
I noticed that both in both tutorial cases and posted fvschemes there is always Code:
div(R) Gauss linear; I tried Code:
div(R) Gauss limitedLinear 1; div(R) Gauss QUICK; div(R) Gauss MUSCL; thanks Uli |
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#23 |
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Senior Member
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Hi! It is for other turbulence model where you use Reynolds stress
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Best regards, Dr. Alexander VAKHRUSHEV Lehrstuhl für Modellierung und Simulation metallurgischer Prozesse / Chair for Modelling and Simulation of Metallurgical Processes Department Metallurgie / Department of Metallurgy Montanuniversität Leoben / University of Leoben Franz-Josef-Str. 18 A - 8700 Leoben Österreich / Austria Tel.: +43 3842 - 402 - 3125 http://smmp.unileoben.ac.at |
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#24 |
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New Member
Join Date: Jun 2012
Posts: 25
Rep Power: 2 ![]() |
Thanks for your reply.
So using a k-Epsilon model does not involve R? But how is it possible that I get different results after switching the scheme for div(R)? |
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#25 |
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Senior Member
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You wrote you get the SAME results. You can easily check which schemes you solver uses, just set "default none;", and you will get errors until you define all schemes.
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Best regards, Dr. Alexander VAKHRUSHEV Lehrstuhl für Modellierung und Simulation metallurgischer Prozesse / Chair for Modelling and Simulation of Metallurgical Processes Department Metallurgie / Department of Metallurgy Montanuniversität Leoben / University of Leoben Franz-Josef-Str. 18 A - 8700 Leoben Österreich / Austria Tel.: +43 3842 - 402 - 3125 http://smmp.unileoben.ac.at |
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#26 |
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New Member
Join Date: Jun 2012
Posts: 25
Rep Power: 2 ![]() |
hi, sorry for the late reply.
I wrote "similar" results since the plots are slightly different. I removed the schemes and it still worked, thanks for your help. |
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