BlockMesh Grading Ambiguity: How to Get Desired y1
Hello all,
I am having trouble getting blockMesh to produce the right y1 for my mesh. If I follow the equations in the User Guide 2.0.0 section 2.1.6.2: Desired y1: 0.0006996 Desired cell size of last cell: 0.15 l = 1.499364 % Length of block n = 100 % Number of cells Therefore: R = 0.15 / 0.0006996 = 214.408 % ratio of last to first cell size r = R^(1/(n-1)) = 1.0557179202 % ratio of each cell to its neighbour Alpha = R (R > 1) Delta_x_s = 0.000370711 % Size of smallest cell Here is the issue: Delta_x_s is supposed to equal my desired y1. The problem is blockMesh grading uses a ratio, R, to define the grading. Therefore if the same factor is applied to both first and last cell, blockMesh will not know the difference: R is the same. The only way to adjust the y1 is then to change the number of cells, I suppose - but that leaves me no control over the number of cells. Is there any way to control both the number of cells and y1? Thanks, Dan |
Hi Dan,
Have you figured this out, if you have then please share ;) Happy new year! Robert |
Hello Robert,
Unfortunately I have not found a solution. Happy New Year, Dan |
Quote:
K |
Hi Karl,
But that would increase the aspect ratio both and eventually will affect the convergence, wouldn't it? Isn't there anyway to control y+ without increasing number of cells and without getting a high enough aspect ratios? Sorry for the rather impetuous question. Regards, Robert |
You mean that the cells next to the wall becomes kind of pancake cells? That is a de facto standard of achieving near wall resolution in more or less all types of meshes. This is generally also ok, as derivatives are largest in the wall-normal direction.
If you want isotropic cells to the wall (like in the case of wall-resolved LES), you can use refineHexMesh on cells adjacent to the wall. Then you will get polyhedral cells in the interface between refined and non-refined cells (hence breaking the constraints of pure hexahedral mesh). Of course this may lead to vast amount of cells. K |
I appear to be slightly late to the party, but it's very simple.
If you have a length L, and divide it by N elements, each element will have a size L/N. Applying an expansion R across the entire length L, means that the first element will have a size (L/N)/sqrt(R) and the last element will have a size (L/N)*sqrt(R). As proof, consider the ratio of the sizes of the first and last elements, you have: (L/N)*sqrt(R) / (L/N)/sqrt(R) = R Hence, if you want to prescribe your desired y1, you would do: y1 = (L/N)/sqrt(R) -----> R = L^2 / (N y1)^2 |
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