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February 19, 2013, 11:59 
Problem with K omega boundary conditions

#1 
Member
Malik
Join Date: Dec 2012
Location: Austin, USA
Posts: 52
Rep Power: 5 
Hi FOAMers !
I am studying some airfoils in 2D and before applying any turbulence model to them I test the model on a cylinder. I tested the komega model which gave me good results with my drag and my strouhal. However, when I want to see the k field in the domain, I see a high value at the inlet (the one I fixed) and then a fast decrease. Do you know why I observe it ? Do you know how to fix this ? My Reynolds is 1000 Here are my boundary conditions : inlet U fixed value 0.015 p zerogradient k fixedValue 0.00000375 epsilon fixedValue 0.0000000112 nut calculated value 0 omega fixedValue 0.037 outlet U zeroGradient p fixedValue 0 k zeroGradient epsilon zeroGradient nut calculated value 0 omega zeroGradient up U symmetryPlane p symmetryPlane k symmetryPlane epsilon symmetryPlane nut symmetryPlane omega symmetryPlane down U symmetryPlane p symmetryPlane k symmetryPlane epsilon symmetryPlane nut symmetryPlane omega symmetryPlane cylinder U fixedvalue 0 p zeroGradient k kqWallfunction 0.00000375 epsilon epsilonWallFunction 0.0000000112 nut nutkWallfunction 0 omega omegaWallFucntion 0.037 frontAndBack U empty p empty k empty epsilon empty nut empty I enclose a screenshot of the kfield with komega so you can see the problem. Thanks a lot for your help 

February 21, 2013, 10:52 

#2 
Member
Malik
Join Date: Dec 2012
Location: Austin, USA
Posts: 52
Rep Power: 5 
Hi all,
since my previous post, I have tried to look at the same case but with komega SST turbulenceModel. I applied the same boundary conditions and found that we had the same jump at the inlet. However this time we have some example of OpenFoam Cases with kOmega SST turbulence model. For example the motorbike. Looking at the inlet, we find the same jump (see attached picture). In fact, what bothers me is that the solution depends on the size of the domain. I don't think we should have this, should we ? There is something that makes me a little more comfortable with this solution which is that the jump is very small. One could say me that we fixed the inlet value quite arbitrarily and that there are no reason why the internalfield would have the same value. But should not we have zero Gradient Boudnary Condition instead ? Thanks for your help 

February 28, 2013, 06:18 

#3 
Member
Roland
Join Date: Mar 2009
Location: Netherlands
Posts: 64
Rep Power: 9 
Hi,
Does reducing turbulent dissipation (epsilon) help? regards, Sylvester 

February 28, 2013, 09:43 

#4 
Senior Member
Olivier
Join Date: Jun 2009
Location: France, grenoble
Posts: 262
Rep Power: 10 
hello,
Your k/epsilon ratio isn't ok. But why don't you try :  turbulentIntensityKineticEnergyInlet for k,  turbulentMixingLengthDissipationRateInlet for epsilon,  turbuelntMixingLengthFrequencyInlet for omega ? regards, olivier 

March 1, 2013, 11:56 

#5 
Member
Malik
Join Date: Dec 2012
Location: Austin, USA
Posts: 52
Rep Power: 5 
Hi and thanks for your answers.
Actually I choosed my Espilon Value at the inlet with this formula : epsilon = k^(3/2) * c mu / l with l, the turbulence length scale. I choosed l = 0,05*D where D is my cylinder's diameter. As sylvester suggested it, I lowered the epsilon value at the inlet and all disappeared. I divided my previous espilon inlet value by 100 (and my omega by 100)to get the first enclosed result. However the nut Field has significantly increased, which seems quite weird to me (2nd enclosed result) Sylvester may be right, I should have chosen a turbulent length scale value lower than 5%. For the boundary conditions, I did not use the turbulent BC simply because I did not know they existed. I just tried to implement it and it required to set the value for k, epsilon and omega, in addition of the turbulent intensity and mixinglength. Furthermore It does not change anything in the solution compared to the case where I only implemented the fixedValue BC. From what you said and what i just tested I really think that I don't know how to define the turbulent length scale. Do you know some experimental formulas I could use ? (I already have looked for it on google but I found no result for external aerodynamic flows). Thanks for your help ! 

April 18, 2015, 17:27 

#6 
New Member
bassam djedi
Join Date: Apr 2015
Posts: 2
Rep Power: 0 
I am doing simulation using openfoam on 2D aerofoil. I used komega model and put all boundary conditions and started the simulation. However, at Time= 26 i receive an error, I hope i can get help with this issue.
Thank you #0 Foam::error:rintStack(Foam::Ostream&) at ??:? #1 Foam::sigFpe::sigHandler(int) at ??:? #2 in "/lib/x86_64linuxgnu/libc.so.6" #3 Foam::GaussSeidelSmoother::smooth(Foam::word const&, Foam::Field<double>&, Foam::lduMatrix const&, Foam::Field<double> const&, Foam::FieldField<Foam::Field, double> const&, Foam::UPtrList<Foam::lduInterfaceField const> const&, unsigned char, int) at ??:? #4 Foam::GaussSeidelSmoother::smooth(Foam::Field<doub le>&, Foam::Field<double> const&, unsigned char, int) const at ??:? #5 Foam::smoothSolver::solve(Foam::Field<double>&, Foam::Field<double> const&, unsigned char) const at ??:? #6 Foam::fvMatrix<double>::solveSegregated(Foam::dict ionary const&) at ??:? #7 Foam::fvMatrix<double>::solve(Foam::dictionary const&) at ??:? #8 Foam::SolverPerformance<double> Foam::solve<double>(Foam::tmp<Foam::fvMatrix<doubl e> > const&) at ??:? #9 Foam::incompressible::RASModels::kOmega::correct() at ??:? #10 at ??:? #11 __libc_start_main in "/lib/x86_64linuxgnu/libc.so.6" #12 at ??:? Floating point exception (core dumped) 

April 19, 2015, 23:25 
Answer

#7 
Senior Member
Khamlaj
Join Date: Nov 2010
Location: United States
Posts: 166
Rep Power: 7 
HeyBassam,
Just zip your files up, and I will fix your problem. Regards, 

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