i have a doubt about mag(U) and mag(internalField(U)) in their results

immortality · April 13, 2013, 05:20

im concluding that in the concept of mag(U) that is defined in for example p folder it uses velocity on the patch and in mag(internalField(U)) it uses magnitude of internal value(neighboring cell),right?
Then When we have defined U as mag(internalField(U)) both should be the same?
Am i correct or not?

immortality · April 14, 2013, 09:45

am i correct?

immortality · April 16, 2013, 17:34

any answer?

immortality · April 20, 2013, 13:31

I mean when we define p as a function of U in 0/p does the solver understands that it should first calculate U(that may be a function of anything) at first and then use that in p equation?
I've tested and am using it and results correctly.
but I'm wondering how does solver knows the arrangement?
why it doesn't go to p folder at first and don't give an error of not have a value on the patch?
does it related to the order that solver uses to calculate fields?
but I examined a reversed process(U a function of p) without any problem in BC.it's very good

but why and how?or I'm speaking on a banal concept?

April 13, 2013, 05:20	i have a doubt about mag(U) and mag(internalField(U)) in their results	#1
immortality Banned ehsan Join Date: Oct 2012 Location: Iran Posts: 1,106 Rep Power: 0	im concluding that in the concept of mag(U) that is defined in for example p folder it uses velocity on the patch and in mag(internalField(U)) it uses magnitude of internal value(neighboring cell),right? Then When we have defined U as mag(internalField(U)) both should be the same? Am i correct or not? Last edited by immortality; April 17, 2013 at 19:38.

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April 14, 2013, 09:45		#2
immortality Banned ehsan Join Date: Oct 2012 Location: Iran Posts: 1,106 Rep Power: 0	am i correct?

April 16, 2013, 17:34		#3
immortality Banned ehsan Join Date: Oct 2012 Location: Iran Posts: 1,106 Rep Power: 0	any answer?

April 20, 2013, 13:31		#4
immortality Banned ehsan Join Date: Oct 2012 Location: Iran Posts: 1,106 Rep Power: 0	I mean when we define p as a function of U in 0/p does the solver understands that it should first calculate U(that may be a function of anything) at first and then use that in p equation? I've tested and am using it and results correctly. but I'm wondering how does solver knows the arrangement? why it doesn't go to p folder at first and don't give an error of not have a value on the patch? does it related to the order that solver uses to calculate fields? but I examined a reversed process(U a function of p) without any problem in BC.it's very good but why and how?or I'm speaking on a banal concept?